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SC2004
Matthias Rüster edited this page Sep 23, 2015
·
6 revisions
echo $(($n+1))
echo $((n+1))
The $
on regular variables in arithmetic contexts is unnecessary, and can even lead to subtle bugs. This is because the contents of $((..))
is first expanded into a string, and then evaluated as an expression:
$ a='1+1'
$ echo $(($a * 5)) # becomes 1+1*5
6
$ echo $((a * 5)) # evaluates as (1+1)*5
10
The $
is unavoidable for special variables like $1
vs 1
, $#
vs #
. ShellCheck does not warn about these cases.