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SC2004
Joachim Ansorg edited this page Nov 12, 2021
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6 revisions
echo $(($n + ${arr[i]}))
echo $((n + arr[i]))
The $
or ${..}
on regular variables in arithmetic contexts is unnecessary, and can even lead to subtle bugs. This is because the contents of $((..))
is first expanded into a string, and then evaluated as an expression:
$ a='1+1'
$ echo $(($a * 5)) # becomes 1+1*5
6
$ echo $((a * 5)) # evaluates as (1+1)*5
10
The $
is unavoidable for special variables like $1
vs 1
, $#
vs #
. It's also required when adding modifiers to parameters expansions, like ${#var}
or ${var%-}
. ShellCheck does not warn about these cases.
The $
is also required (and not warned about) when you need to specify the base for a variable value:
$ a=09
$ echo $((a + 1)) # leading zero forces octal interpretation
bash: 09: value too great for base (error token is "09")
$ echo $((10#a + 1))
bash: 10#a: value too great for base (error token is "10#a")
$ echo $((10#$a + 1))
10