string: rename b to buf in string.replace_each to avoid sort lambda shadowing #26510
+8
−8
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Summary
replace_each(),idxs.sort(a.idx < b.idx)usesbas the sort lambda parametermut bdeclaration on the next line shadows it, causing the compiler to resolvebin the sort expression to the wrong variableb/b_itobuf/buf_ito eliminate the name conflictTest plan
v test vlib/builtin/— 32 passed, 1 skipped, 0 failedreplace_each🤖 Generated with Claude Code