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typos
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victorballester7 committed Dec 31, 2023
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Expand Up @@ -1069,9 +1069,9 @@
\begin{proof}
From the superquadradicity condition, for $t>0$, the function $\abs{t}^{-p}F(x,t)$ is nondecreasing (the derivative is nonnegative). So, for $0\leq t\leq 1$ we have $F(x,t)\leq \abs{t}^p F(x,1)$. Similarly, for $-1\leq t\leq 0$ we have $F(x,t)\leq \abs{t}^p F(x,-1)$. Using the upper estimate we get, for $\abs{t}\geq 1$, $\abs{F(x,t)}\leq \overline{\overline{C}} \abs{t}^{p_1}$ and so
$\abs{F(x,t)}\leq C'(\abs{t}^p+\abs{t}^{p_1})$ $\forall t$ (the positivity of $F(x,1)$ and $F(x,-1)$ follows from the third hypothesis on $f$). So:
$$
\int_\Omega \abs{F(x,u)}\leq C'\left(\norm{u}_{
$$
% $$
% \int_\Omega \abs{F(x,u)}\leq C'\left(\norm{u}_{
% $$
\end{proof}
\end{multicols}
\end{document}

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