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Correct mA to A conversion in Power-Monitoring-Calibration.md #1439

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Correct mA to A conversion in Power-Monitoring-Calibration.md #1439

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Correct mA to A conversion in Power-Monitoring-Calibration.md
schnellecom Dec 22, 2024
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Update Power-Monitoring-Calibration.md
schnellecom Dec 23, 2024
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13 changes: 9 additions & 4 deletions docs/Power-Monitoring-Calibration.md
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Expand Up @@ -35,16 +35,21 @@
[`VoltageSet <voltage>`](Commands.md#voltageset)
_Replace `<voltage>` with your standard voltage or with reading on your multi-meter if you have one. Your voltage will vary depending on the electrical standards and your electrical grid_

3. Verify the **Current** reading by calculating current value (amperage) using this formula: **P<sub>(W)</sub>/V<sub>(V)</sub>=I<sub>(A)</sub>**. Adjust the current offset if needed (in milliAmps (mA=A\*1000)):
3. Verify the **Current** reading by calculating current value (amperage) using this formula: **P<sub>(W)</sub>/V<sub>(V)</sub>=I<sub>(A)</sub>**. Adjust the current offset if needed (in milliAmps ($1000mA=1A$)):
[`CurrentSet <current>`](Commands.md#currentset)
_Replace `<current>` with your calculated value (in milliAmps)_

`CurrentSet` calculation:
P/V=I
1000 * Watts/Volts = milliAmperes
$$\frac{Watts}{Volts}=Amps$$

and thus

$$1000 \* \frac{Watts}{Volts} = milliAmps$$

!!! example
1000*(60.0/235.5) = 254.777
Consider a power usage of $60W$ at a voltage of $240V$. Then the current in milliAmps can be calculated as

$$1000 \* \frac{60}{240} = 240.0$$
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According to my calculator is (60 / 240) * 1000 = 250 ?!?

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You are completely correct, I have changed it to hopefully now be right. Thanks for the comment :)


4. Confirm the validity of your calibration process checking `Power Factor` from the web UI which should be as close as possible to `1.00`. In theory resistive loads will always provide a power factor of 1.00. If that is not the case, we recommend you repeat the calibration process and make sure everything was done correctly.

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