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simplify by: depth + prefix.bit_len()== point #3

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@zhiqiangxu zhiqiangxu commented Apr 9, 2024

The test shows bit_len() == point - depth is always true as long as point >= depth.

So depth + prefix.bit_len() is the same as depth + point - depth, which is depth.

(if point < depth, PathSegment::from_path will panic anyway.)

This PR also fixed the calculation of max_bit_len.

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