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AddOneRow.cpp #34

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80 changes: 80 additions & 0 deletions AddOneRow.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,80 @@
// Given the root of a binary tree and two integers val and depth, add a row of nodes with value val at the given depth depth.

// Note that the root node is at depth 1.

// The adding rule is:

// Given the integer depth, for each not null tree node cur at the depth depth - 1, create two tree nodes with value val as cur's left subtree root and right subtree root.
// cur's original left subtree should be the left subtree of the new left subtree root.
// cur's original right subtree should be the right subtree of the new right subtree root.
// If depth == 1 that means there is no depth depth - 1 at all, then create a tree node with value val as the new root of the whole original tree, and the original tree is the new root's left subtree.



/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* addOneRow(TreeNode* root, int val, int depth) {

if(root==NULL)
return NULL;

if(depth==1)
{
TreeNode* newNode=new TreeNode(val);
newNode->left=root;
return newNode;
}

queue<TreeNode*>q;
q.push(root);

int height=0;

while(!q.empty())
{
height++;

if(height==depth-1)
break;

int n=q.size();
while(n--)
{
TreeNode* node= q.front();
q.pop();
if(node->left)
q.push(node->left);

if(node->right)
q.push(node->right);
}
}
int n=q.size();
while(n--)
{
TreeNode* node= q.front();
q.pop();
TreeNode* newNode = new TreeNode(val);
newNode -> left = node -> left;
node -> left = newNode;


TreeNode* newNode2 = new TreeNode(val);
newNode2 -> right = node -> right;
node -> right = newNode2;

}
return root;
}
};