Feature official templates #10
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| try: | ||
| if not os.path.exists(secrets_dir): | ||
| logger.warning(f"Secrets directory does not exist: {secrets_dir}") |
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Clear-text logging of sensitive information High
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AI about 1 month ago
To fix this problem, we should revise the log message on line 212 so that it no longer prints the full path to the secrets directory. Instead, we can log a more generic message such as "Secrets directory does not exist" or "Secrets directory missing", which is still informative for debugging purposes but does not disclose the directory path.
We only need to change line 212 in template/python-connector/index.py. No imports or new definitions are required.
| @@ -209,7 +209,7 @@ | ||
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| try: | ||
| if not os.path.exists(secrets_dir): | ||
| logger.warning(f"Secrets directory does not exist: {secrets_dir}") | ||
| logger.warning("Secrets directory does not exist.") | ||
| return {} | ||
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| for filename in os.listdir(secrets_dir): |
| logger.debug(f"Loaded {len(context.secrets) if context.secrets else 0} secrets") | ||
| except ValueError as e: # Config errors from Context validation | ||
| logger.error(f"Configuration error: {e}") | ||
| return {"statusCode": 500, "body": {"error": str(e)}}, 500 |
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Information exposure through an exception Medium
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AI about 1 month ago
To fix the problem, we should replace the error response in line 284 so that it does not expose the contents of str(e) to the user. Instead, we should return a generic error message, such as "Configuration error", or simply "Internal server error". Optionally, for diagnostics, we should continue logging the detailed error message internally, as already done on line 283. This ensures that the developers can debug issues based on the logged messages, but external users will not see any sensitive details. The change is limited to the except block handling ValueError in the call_handler function, specifically line 284.
| @@ -281,7 +281,7 @@ | ||
| logger.debug(f"Loaded {len(context.secrets) if context.secrets else 0} secrets") | ||
| except ValueError as e: # Config errors from Context validation | ||
| logger.error(f"Configuration error: {e}") | ||
| return {"statusCode": 500, "body": {"error": str(e)}}, 500 | ||
| return {"statusCode": 500, "body": {"error": "Configuration error"}}, 500 | ||
| except Exception as e: # Unexpected errors | ||
| logger.error(f"Unexpected error during initialization: {e}") | ||
| return {"statusCode": 500, "body": {"error": "Internal server error"}}, 500 |
| ) | ||
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| logger.debug(f"Using {debug_library} debugger on {debug_host}:{debug_port}.") | ||
| app.run(host="0.0.0.0", port=5000, debug=True, use_debugger=False, use_reloader=False) |
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Flask app is run in debug mode High
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AI about 1 month ago
To fix this issue, we should ensure that the Flask application is never run with debug=True outside of a strictly local, trusted development context. In practical terms, this means replacing debug=True with debug=False in the app.run() call on line 344. Since we are handling external debugging integrations, it's most secure to use waitress everywhere in production-like flows. If local debugging with Flask's development server is allowed (and explicitly required), debug=True should only ever be set when it is absolutely certain the context is safe (such as localhost only)—but here, to follow best practices, it is safest to remove debug=True entirely and advise using a proper debugger/IDE integration if needed. The simplest way is to set debug=False, ensuring no interactive debugger is exposed. Only line 344 in template/python-connector/index.py needs editing.
| @@ -341,6 +341,6 @@ | ||
| ) | ||
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| logger.debug(f"Using {debug_library} debugger on {debug_host}:{debug_port}.") | ||
| app.run(host="0.0.0.0", port=5000, debug=True, use_debugger=False, use_reloader=False) | ||
| app.run(host="0.0.0.0", port=5000, debug=False, use_debugger=False, use_reloader=False) | ||
| else: | ||
| serve(app, host="0.0.0.0", port=5000) |
| ) | ||
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| logger.debug(f"Using {debug_library} debugger on {debug_host}:{debug_port}.") | ||
| app.run(host="0.0.0.0", port=5000, debug=True, use_debugger=False, use_reloader=False) |
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Flask app is run in debug mode High
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AI about 1 month ago
To fix the problem, you should ensure that the Flask application is never run with debug=True. Instead, rely on the mechanism that utilizes external debuggers (such as debugpy or pycharm) for development debugging. Remove the debug=True argument from app.run(...), and only set it to False (or omit it, as the default is False). If you need debugging tools for development, use the attached debuggers rather than Flask's built-in debug mode. This change should be applied in template/python-function-common/index.py on line 112. No further code or dependency changes are required.
| @@ -109,6 +109,6 @@ | ||
| ) | ||
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| logger.debug(f"Using {debug_library} debugger on {debug_host}:{debug_port}.") | ||
| app.run(host="0.0.0.0", port=5000, debug=True, use_debugger=False, use_reloader=False) | ||
| app.run(host="0.0.0.0", port=5000, debug=False, use_debugger=False, use_reloader=False) | ||
| else: | ||
| serve(app, host="0.0.0.0", port=5000) |
Adding separate templates hyper-focused on each connectors, common functions.