Container with Most Water Problem:

[naveen-sivaraj]

def max_area(height):
"""
Finds the maximum amount of water a container can store between two vertical lines.

Args:
    height (list of int): A list of non-negative integers representing the height of vertical lines.

Returns:
    int: The maximum area of water that can be contained.

Example:
    >>> max_area([1,8,6,2,5,4,8,3,7])
    49

Explanation:
    The maximum area is formed between the lines at indices 1 and 8 (height 8 and 7),
    giving an area of 49 (width = 7, height = 7).
"""
left = 0
right = len(height) - 1
max_area = 0

while left < right:

    width = right - left
    h = min(height[left], height[right])
    current_area = width * h
    max_area = max(max_area, current_area)

  
    if height[left] < height[right]:
        left += 1
    else:
        right -= 1

return max_area

if name == "main":
heights = [1, 8, 6, 2, 5, 4, 8, 3, 7]
print(f"The maximum water area is: {max_area(heights)}")

[vercel]

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