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added SpiralMatrix.java
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Kevin Naughton Jr authored and Kevin Naughton Jr committed Jun 5, 2018
1 parent e815a7c commit df4ee95
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61 changes: 61 additions & 0 deletions company/google/SpiralMatrix.java
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@@ -0,0 +1,61 @@
//Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
//
//Example 1:
//
//Input:
//[
//[ 1, 2, 3 ],
//[ 4, 5, 6 ],
//[ 7, 8, 9 ]
//]
//Output: [1,2,3,6,9,8,7,4,5]
//Example 2:
//
//Input:
//[
//[1, 2, 3, 4],
//[5, 6, 7, 8],
//[9,10,11,12]
//]
//Output: [1,2,3,4,8,12,11,10,9,5,6,7]

class SpiralMatrix {
public List<Integer> spiralOrder(int[][] matrix) {
List<Integer> result = new ArrayList<Integer>();
if(matrix == null || matrix.length == 0) {
return result;
}

int rowStart = 0;
int rowEnd = matrix.length - 1;
int colStart = 0;
int colEnd = matrix[0].length - 1;
while(rowStart <= rowEnd && colStart <= colEnd) {
for(int i = colStart; i <= colEnd; i++) {
result.add(matrix[rowStart][i]);
}
rowStart++;

for(int i = rowStart; i <= rowEnd; i++) {
result.add(matrix[i][colEnd]);
}
colEnd--;

if(rowStart <= rowEnd) {
for(int i = colEnd; i >= colStart; i--) {
result.add(matrix[rowEnd][i]);
}
}
rowEnd--;

if(colStart <= colEnd) {
for(int i = rowEnd; i >= rowStart; i--) {
result.add(matrix[i][colStart]);
}
}
colStart++;
}

return result;
}
}
61 changes: 61 additions & 0 deletions company/microsoft/SpiralMatrix.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,61 @@
//Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
//
//Example 1:
//
//Input:
//[
//[ 1, 2, 3 ],
//[ 4, 5, 6 ],
//[ 7, 8, 9 ]
//]
//Output: [1,2,3,6,9,8,7,4,5]
//Example 2:
//
//Input:
//[
//[1, 2, 3, 4],
//[5, 6, 7, 8],
//[9,10,11,12]
//]
//Output: [1,2,3,4,8,12,11,10,9,5,6,7]

class SpiralMatrix {
public List<Integer> spiralOrder(int[][] matrix) {
List<Integer> result = new ArrayList<Integer>();
if(matrix == null || matrix.length == 0) {
return result;
}

int rowStart = 0;
int rowEnd = matrix.length - 1;
int colStart = 0;
int colEnd = matrix[0].length - 1;
while(rowStart <= rowEnd && colStart <= colEnd) {
for(int i = colStart; i <= colEnd; i++) {
result.add(matrix[rowStart][i]);
}
rowStart++;

for(int i = rowStart; i <= rowEnd; i++) {
result.add(matrix[i][colEnd]);
}
colEnd--;

if(rowStart <= rowEnd) {
for(int i = colEnd; i >= colStart; i--) {
result.add(matrix[rowEnd][i]);
}
}
rowEnd--;

if(colStart <= colEnd) {
for(int i = rowEnd; i >= rowStart; i--) {
result.add(matrix[i][colStart]);
}
}
colStart++;
}

return result;
}
}
61 changes: 61 additions & 0 deletions company/uber/SpiralMatrix.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,61 @@
//Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
//
//Example 1:
//
//Input:
//[
//[ 1, 2, 3 ],
//[ 4, 5, 6 ],
//[ 7, 8, 9 ]
//]
//Output: [1,2,3,6,9,8,7,4,5]
//Example 2:
//
//Input:
//[
//[1, 2, 3, 4],
//[5, 6, 7, 8],
//[9,10,11,12]
//]
//Output: [1,2,3,4,8,12,11,10,9,5,6,7]

class SpiralMatrix {
public List<Integer> spiralOrder(int[][] matrix) {
List<Integer> result = new ArrayList<Integer>();
if(matrix == null || matrix.length == 0) {
return result;
}

int rowStart = 0;
int rowEnd = matrix.length - 1;
int colStart = 0;
int colEnd = matrix[0].length - 1;
while(rowStart <= rowEnd && colStart <= colEnd) {
for(int i = colStart; i <= colEnd; i++) {
result.add(matrix[rowStart][i]);
}
rowStart++;

for(int i = rowStart; i <= rowEnd; i++) {
result.add(matrix[i][colEnd]);
}
colEnd--;

if(rowStart <= rowEnd) {
for(int i = colEnd; i >= colStart; i--) {
result.add(matrix[rowEnd][i]);
}
}
rowEnd--;

if(colStart <= colEnd) {
for(int i = rowEnd; i >= rowStart; i--) {
result.add(matrix[i][colStart]);
}
}
colStart++;
}

return result;
}
}
61 changes: 61 additions & 0 deletions leetcode/array/SpiralMatrix.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,61 @@
//Given a matrix of m x n elements (m rows, n columns), return all elements of the matrix in spiral order.
//
//Example 1:
//
//Input:
//[
//[ 1, 2, 3 ],
//[ 4, 5, 6 ],
//[ 7, 8, 9 ]
//]
//Output: [1,2,3,6,9,8,7,4,5]
//Example 2:
//
//Input:
//[
//[1, 2, 3, 4],
//[5, 6, 7, 8],
//[9,10,11,12]
//]
//Output: [1,2,3,4,8,12,11,10,9,5,6,7]

class SpiralMatrix {
public List<Integer> spiralOrder(int[][] matrix) {
List<Integer> result = new ArrayList<Integer>();
if(matrix == null || matrix.length == 0) {
return result;
}

int rowStart = 0;
int rowEnd = matrix.length - 1;
int colStart = 0;
int colEnd = matrix[0].length - 1;
while(rowStart <= rowEnd && colStart <= colEnd) {
for(int i = colStart; i <= colEnd; i++) {
result.add(matrix[rowStart][i]);
}
rowStart++;

for(int i = rowStart; i <= rowEnd; i++) {
result.add(matrix[i][colEnd]);
}
colEnd--;

if(rowStart <= rowEnd) {
for(int i = colEnd; i >= colStart; i--) {
result.add(matrix[rowEnd][i]);
}
}
rowEnd--;

if(colStart <= colEnd) {
for(int i = rowEnd; i >= rowStart; i--) {
result.add(matrix[i][colStart]);
}
}
colStart++;
}

return result;
}
}

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