jv_mem_calloc(): always call with (nmemb, size) #2978
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It does not matter much since they most likely just get multiplied together, but some compilers would complain about this if these were calls to calloc.
wader
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Dec 11, 2023
emanuele6
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It does not matter much since they most likely just get multiplied
together, but some compilers would complain about this if these were
calls to calloc.