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109 changes: 109 additions & 0 deletions number/min_of_mod_of_linear.hpp
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#pragma once

#include <cassert>
#include <vector>
#include <utility>

// min((ax + b) mod m) for 0 <= x < n
// 0 < n, 0 < m <= 1e9
// https://maspypy.com/library-checker-min-of-mod-of-linear
template <class Int = int, class Long = long long>
auto min_of_mod_of_linear(Int n, const Int &m, Int a, Int b) {

// p = (xs, ys), v = (dx, dy) として
// 列 (p, p + v, ..., p + (len - 1)v) が点群全体を包絡する
struct Result {
Int xs, ys;
Int dx, dy;
Int len;

Int min() const { return ys + dy * (len - 1); }
};

assert(0 < n);
assert(0 < m);

if (n > m) n = m;
a = (m - a % m) % m;
b = (b % m + m) % m;

Int x = 0, y = b;

Int p = 0, q = 1, r = 1, s = 0; // p/q <= a/m < r/s

std::vector<Result> ret{Result{x, y, 0, 0, 1}};

while (true) {
if (x + q > n - 1) break;

const Long aqmp = (Long)a * q - (Long)m * p;
if (aqmp == 0) break; // p/q == a/m

const Long mras = (Long)m * r - (Long)a * s;

assert(aqmp > 0);
assert(mras > 0);

if (const Long num = p + r, den = q + s; num * m <= den * a) { // num/den <= a/m 下側を更新

// q + is <= n - 1 - x

// (p + ir) / (q + is) <= a/m (下側である条件) i >= 0
// <=> m(p + ir) <= a(q + is) <=> (mr - as)i <= aq - mp

// a(q + is) - m(p + ir) <= Y (改善する条件) i >= 0
// (mr - as)i >= aq - mp - Y

const Long iub = aqmp / mras;

const Long imp_i_lb = std::max<Long>((std::max<Long>(aqmp - y, 0) + mras - 1) / mras, 0);

if (imp_i_lb <= iub) {
p += imp_i_lb * r;
q += imp_i_lb * s;

const Long c = (Long)a * q - (Long)m * p;
assert(0 <= c);
assert(c <= y);

const Long kub = y / c;
const Long k = std::min<Long>(kub, (n - 1 - x) / q);

if (k) ret.push_back(Result{x + q, (Int)(y - c), q, (Int)-c, (Int)k});

x += q * k;
y -= c * k;
if (k < kub) break;
continue;
} else {
p += iub * r;
q += iub * s;
}
} else { // num/den > a/m 上側を更新
// (r + ip)/(s + iq) > a/m <=> m(r + ip) > a(s + iq) <=> (aq - mp)i < mr - as
// -> i step 進んでもまだ超えない

const Long i = (mras - 1) / aqmp;
assert(i > 0);

// x + (s + iq) <= n - 1
// const Long iub = (n - 1 - q - x - s) / q;
// if (i > iub) break;

r += (i - 1) * p; // NOTE: overflow
s += (i - 1) * q;

// まだ a/m < (p + r) / (q + s)
assert((Long)a * (q + s) < (Long)m * (p + r));

r += p;
s += q;

// 逆転
assert((Long)a * (q + s) >= (Long)m * (p + r));
}
}

// return y;
return ret;
}
17 changes: 17 additions & 0 deletions number/test/min_of_mod_of_linear.test.cpp
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#define PROBLEM "https://judge.yosupo.jp/problem/min_of_mod_of_linear"

Check failure on line 1 in number/test/min_of_mod_of_linear.test.cpp

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#include "../min_of_mod_of_linear.hpp"
#include <iostream>
using namespace std;

int main() {
cin.tie(nullptr), ios::sync_with_stdio(false);

int T;
cin >> T;
while (T--) {
int n, m, a, b;
cin >> n >> m >> a >> b;
cout << min_of_mod_of_linear<int, long long>(n, m, a, b).back().min() << '\n';
}
}
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