equalish

equal^ish, compare two lists to know if they are structurally in equal (alike)

Two lists are considered to be equalish, when:

[1, 2, [3, 4], 5] equalish [1,2,[3,4],5] true

[{"a":"1", "b":"2"}, 1, 2, [8, 9, [10, 12]], 12] equalish [{"a":"1", "b":"2"}, 1, 2, [8, 9, [10, 12]], 12] true

Or it could even be more ~ish by allowing element in different order

[1, 2, [3, 4], 5] equalish [1,2,5, [4,3]] true

It could compare nested list/map structure

[1, 2, [5,[3,2]], 7, {"a", "1", "b": "2", "c":[11, 12]}] equalish [1, 2, [5,[3,2]], 7, {"a", "1", "b": "2", "c":[11, 12]}] true

API

public static <T> boolean equalish(List<T> a, List<T> b, boolean honorOrder)
a,b: the two list to compare to
honorOrder: if or not comparing order

Usage

List<Object> l11 = new ArrayList<>();
        l11.add(8);
        l11.add(7);

        List<Object> l1 = new ArrayList<>();
        l1.add(1);
        l1.add(3);
        l1.add(2);
        l1.add(l11);
        l1.add(7);



        List<Object> l21 = new ArrayList<>();
        l21.add(7);
        l21.add(8);

        List<Object> l2 = new ArrayList<>();
        l2.add(1);
        l2.add(l21);
        l2.add(3);
        l2.add(2);
        l2.add(7);

        boolean isqualish = ListEqualish.equalish(l1, l2, false);