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Refactored docs.
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codeplea committed Jan 25, 2016
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175 changes: 90 additions & 85 deletions README.md
Original file line number Diff line number Diff line change
Expand Up @@ -26,30 +26,91 @@ Here is a minimal example to evaluate an expression at runtime.

```C
#include "tinyexpr.h"
#include <stdio.h>
printf("%f\n", te_interp("5*5", 0)); /* Prints 25. */
```
int main(int argc, char *argv[])
{
const char *c = "sqrt(5^2+7^2+11^2+(8-2)^2)";
double r = te_interp(c, 0);
printf("The expression:\n\t%s\nevaluates to:\n\t%f\n", c, r);
return 0;
}
##Usage
TINYEXPR defines only four functions:
```C
double te_interp(const char *expression, int *error);
te_expr *te_compile(const char *expression, const te_variable *variables, int var_count, int *error);
double te_eval(const te_expr *n);
void te_free(te_expr *n);
```

##te_interp
```C
double te_interp(const char *expression, int *error);
```
`te_interp()` takes an expression and immediately returns the result of it. If there
is a parse error, `te_interp()` returns NaN.
If the `error` pointer argument is not 0, then `te_interp()` will set `*error` to the position
of the parse error on failure, and set `*error` to 0 on success.
**example usage:**
```C
int error;
double a = te_interp("(5+5)", 0); /* Returns 10. */
double a = te_interp("(5+5)", &error); /* Returns 10, error is set to 0. */
double b = te_interp("(5+5", &error); /* Returns NaN, error is set to 4. */
```

##te_compile, te_eval, te_free
```C
te_expr *te_compile(const char *expression, const te_variable *lookup, int lookup_len, int *error);
double te_eval(const te_expr *n);
void te_free(te_expr *n);
```
Give `te_compile()` an expression with unbound variables and a list of
variable names and pointers. `te_compile()` will return a `te_expr*` which can
be evaluated later using `te_eval()`. On failure, `te_compile()` will return 0
and optionally set the passed in `*error` to the location of the parse error.
You may also compile expressions without variables by passing `te_compile()`'s second
and thrid arguments as 0.
Give `te_eval()` a `te_expr*` from `te_compile()`. `te_eval()` will evaluate the expression
using the current variable values.
After you're finished, make sure to call `te_free()`.
**example usage:**
```C
double x, y;
/* Store variable names and pointers. */
te_variable vars[] = {{"x", &x}, {"y", &y}};
int err;
/* Compile the expression with variables. */
te_expr *expr = te_compile("sqrt(x^2+y^2)", vars, 2, &err);
if (expr) {
x = 3; y = 4;
const double h1 = te_eval(expr); /* Returns 5. */
That produces the following output:
x = 5; y = 12;
const double h2 = te_eval(expr); /* Returns 13. */
The expression:
sqrt(5^2+7^2+11^2+(8-2)^2)
evaluates to:
15.198684
te_free(expr);
} else {
printf("Parse error at %d\n", err);
}
```

##Longer Example

Here is an example that will evaluate an expression passed in from the command
line. It also does error checking and binds the variables *x* and *y*.
Here is a complete example that will evaluate an expression passed in from the command
line. It also does error checking and binds the variables `x` and `y` to *3* and *4*, respectively.

```C
#include "tinyexpr.h"
Expand All @@ -58,7 +119,7 @@ line. It also does error checking and binds the variables *x* and *y*.
int main(int argc, char *argv[])
{
if (argc < 2) {
printf("Usage: example2 \"expression\"\n", argv[0]);
printf("Usage: example2 \"expression\"\n");
return 0;
}

Expand All @@ -74,21 +135,18 @@ line. It also does error checking and binds the variables *x* and *y*.
int err;
te_expr *n = te_compile(expression, vars, 2, &err);

if (!err) {
if (n) {
/* The variables can be changed here, and eval can be called as many
* times as you like. This is fairly efficient because the parsing has
* already been done. */
x = 3;
y = 4;
const double r = te_eval(n); printf("Result:\n\t%f\n", r); }
else {
x = 3; y = 4;
const double r = te_eval(n); printf("Result:\n\t%f\n", r);
te_free(n);
} else {
/* Show the user where the error is at. */
printf("\t%*s^\nError near here", err-1, "");
}

/* te_free is safe to call on null. */
te_free(n);
return 0;
}
```
Expand All @@ -110,87 +168,37 @@ This produces the output:
5.000000
##Usage

TINYEXPR defines only five functions:

```C
double te_interp(const char *expression, int *error);
te_expr *te_compile(const char *expression, const te_variable *lookup, int lookup_len, int *error);
double te_eval(const te_expr *n);
void te_print(const te_expr *n);
void te_free(te_expr *n);
```
**te_interp** takes an expression and immediately returns the result of it. If
an error pointer is passed in, *te_interp* will set it to 0 for success or
approximately the position of the error for failure. If you don't care about
errors, just pass in 0. *te_interp* will return NaN for bad expressions regardless.
**te_interp example:**
```C
double x = te_interp("5+5", 0);
```

**te_compile** will compile an expression with unbound variables, which will
be suitable to evaluate later. **te_eval** can then be called on the compiled
expression repeatedly to evaluate it with different variable values. **te_free**
should be called after you're finished.

**te_compile example:**

```C
double x, y;
te_variable vars[] = {{"x", &x}, {"y", &y}};

int err;
te_expr *expr = te_compile("sqrt(x^2+y^2)", vars, 2, &err);

if (!err) {
x = 3; y = 4;
const double h1 = te_eval(expr);

x = 5; y = 7;
const double h2 = te_eval(expr);
}

te_free(expr);
```
**te_print** will display some (possibly not so) useful debugging
information about the return value of *te_compile*.
##How it works
**te_compile** uses a simple recursive descent parser to compile your
expression into a syntax tree. For example, the expression "sin x + 1/4"
`te_compile()` uses a simple recursive descent parser to compile your
expression into a syntax tree. For example, the expression `"sin x + 1/4"`
parses as:
![example syntax tree](doc/e1.png?raw=true)
**te_compile** also automatically prunes constant branches. In this example,
the compiled expression returned by *te_compile* is:
`te_compile()` also automatically prunes constant branches. In this example,
the compiled expression returned by `te_compile()` would become:
![example syntax tree](doc/e2.png?raw=true)
**te_eval** will automatically load in any variables by their pointer, then evaluate
`te_eval()` will automatically load in any variables by their pointer, and then evaluate
and return the result of the expression.
**te_free** should always be called when you're done with the compiled expression.
`te_free()` should always be called when you're done with the compiled expression.
##Speed
TINYEXPR is pretty fast compared to C when the expression is short, when the
expression does hard calculations (e.g. exponentiation), and when some of the
work can be simplified by *te_compile*. TINYEXPR is slow compared to C when the
work can be simplified by `te_compile()`. TINYEXPR is slow compared to C when the
expression is long and involves only basic arithmetic.
Here is some example performance numbers taken from the included
*benchmark.c* program:
**benchmark.c** program:
| Expression | te_eval time | native C time | slowdown |
| :------------- |-------------:| -----:|----:|
Expand Down Expand Up @@ -235,9 +243,6 @@ In addition, the following C math functions are also supported:
- All functions/types start with the letters *te*.
- If there is an error, you can usually still evaluate the first part of the
expression. This may or may not be useful to you.
- To allow constant optimization, surround constant expressions in parentheses.
For example "x+(1+5)" will evaluate the "(1+5)" expression at compile time and
compile the entire expression as "x+6", saving a runtime calculation. The
Expand Down
13 changes: 6 additions & 7 deletions example2.c
Original file line number Diff line number Diff line change
Expand Up @@ -20,20 +20,19 @@ int main(int argc, char *argv[])
int err;
te_expr *n = te_compile(expression, vars, 2, &err);

if (!err) {
if (n) {
/* The variables can be changed here, and eval can be called as many
* times as you like. This is fairly efficient because the parsing has
* already been done. */
x = 3;
y = 4;
const double r = te_eval(n); printf("Result:\n\t%f\n", r); }
else {
x = 3; y = 4;
const double r = te_eval(n); printf("Result:\n\t%f\n", r);

te_free(n);
} else {
/* Show the user where the error is at. */
printf("\t%*s^\nError near here", err-1, "");
}

/* te_free is safe to call on null. */
te_free(n);

return 0;
}

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