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Updating Sphinx docs - branch (singlehtml)
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branches/master/singlehtml/_downloads/15487131c52c6487f27ab78c60499d37/1d_stencil_1.cpp
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// Copyright (c) 2014 Hartmut Kaiser | ||
// Copyright (c) 2014 Patricia Grubel | ||
// | ||
// SPDX-License-Identifier: BSL-1.0 | ||
// Distributed under the Boost Software License, Version 1.0. (See accompanying | ||
// file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt) | ||
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// This is the first in a series of examples demonstrating the development of a | ||
// fully distributed solver for a simple 1D heat distribution problem. | ||
// | ||
// This example provides a serial base line implementation. No parallelization | ||
// is performed. | ||
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#include <hpx/chrono.hpp> | ||
#include <hpx/init.hpp> | ||
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#include <cstddef> | ||
#include <cstdint> | ||
#include <iostream> | ||
#include <vector> | ||
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#include "print_time_results.hpp" | ||
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/////////////////////////////////////////////////////////////////////////////// | ||
// Command-line variables | ||
bool header = true; // print csv heading | ||
double k = 0.5; // heat transfer coefficient | ||
double dt = 1.; // time step | ||
double dx = 1.; // grid spacing | ||
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/////////////////////////////////////////////////////////////////////////////// | ||
//[stepper_1 | ||
struct stepper | ||
{ | ||
// Our partition type | ||
typedef double partition; | ||
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// Our data for one time step | ||
typedef std::vector<partition> space; | ||
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// Our operator | ||
static double heat(double left, double middle, double right) | ||
{ | ||
return middle + (k * dt / (dx * dx)) * (left - 2 * middle + right); | ||
} | ||
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// do all the work on 'nx' data points for 'nt' time steps | ||
space do_work(std::size_t nx, std::size_t nt) | ||
{ | ||
// U[t][i] is the state of position i at time t. | ||
std::vector<space> U(2); | ||
for (space& s : U) | ||
s.resize(nx); | ||
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// Initial conditions: f(0, i) = i | ||
for (std::size_t i = 0; i != nx; ++i) | ||
U[0][i] = double(i); | ||
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// Actual time step loop | ||
for (std::size_t t = 0; t != nt; ++t) | ||
{ | ||
space const& current = U[t % 2]; | ||
space& next = U[(t + 1) % 2]; | ||
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next[0] = heat(current[nx - 1], current[0], current[1]); | ||
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for (std::size_t i = 1; i != nx - 1; ++i) | ||
next[i] = heat(current[i - 1], current[i], current[i + 1]); | ||
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next[nx - 1] = heat(current[nx - 2], current[nx - 1], current[0]); | ||
} | ||
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// Return the solution at time-step 'nt'. | ||
return U[nt % 2]; | ||
} | ||
}; | ||
//] | ||
/////////////////////////////////////////////////////////////////////////////// | ||
int hpx_main(hpx::program_options::variables_map& vm) | ||
{ | ||
std::uint64_t nx = | ||
vm["nx"].as<std::uint64_t>(); // Number of grid points. | ||
std::uint64_t nt = vm["nt"].as<std::uint64_t>(); // Number of steps. | ||
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if (vm.count("no-header")) | ||
header = false; | ||
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// Create the stepper object | ||
stepper step; | ||
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// Measure execution time. | ||
std::uint64_t t = hpx::chrono::high_resolution_clock::now(); | ||
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// Execute nt time steps on nx grid points. | ||
stepper::space solution = step.do_work(nx, nt); | ||
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// Print the final solution | ||
if (vm.count("results")) | ||
{ | ||
for (std::size_t i = 0; i != nx; ++i) | ||
std::cout << "U[" << i << "] = " << solution[i] << std::endl; | ||
} | ||
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std::uint64_t elapsed = hpx::chrono::high_resolution_clock::now() - t; | ||
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std::uint64_t const os_thread_count = hpx::get_os_thread_count(); | ||
print_time_results(os_thread_count, elapsed, nx, nt, header); | ||
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return hpx::local::finalize(); | ||
} | ||
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int main(int argc, char* argv[]) | ||
{ | ||
namespace po = hpx::program_options; | ||
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// clang-format off | ||
po::options_description desc_commandline; | ||
desc_commandline.add_options() | ||
("results", "print generated results (default: false)") | ||
("nx", po::value<std::uint64_t>()->default_value(100), | ||
"Local x dimension") | ||
("nt", po::value<std::uint64_t>()->default_value(45), | ||
"Number of time steps") | ||
("k", po::value<double>(&k)->default_value(0.5), | ||
"Heat transfer coefficient (default: 0.5)") | ||
("dt", po::value<double>(&dt)->default_value(1.0), | ||
"Timestep unit (default: 1.0[s])") | ||
("dx", po::value<double>(&dx)->default_value(1.0), | ||
"Local x dimension") | ||
( "no-header", "do not print out the csv header row") | ||
; | ||
// clang-format on | ||
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// Initialize and run HPX | ||
hpx::local::init_params init_args; | ||
init_args.desc_cmdline = desc_commandline; | ||
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return hpx::local::init(hpx_main, argc, argv, init_args); | ||
} |
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...hes/master/singlehtml/_downloads/2b583c3b9d65dd88ffc89d3a51ba81d8/interest_calculator.cpp
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/////////////////////////// Interest Calculator /////////////////////////////// | ||
// Copyright (c) 2012 Adrian Serio | ||
// | ||
// SPDX-License-Identifier: BSL-1.0 | ||
// Distributed under the Boost Software License, Version 1.0. (See accompanying | ||
// file LICENSE_1_0.txt or copy at http://www.boost.org/LICENSE_1_0.txt) | ||
// | ||
// Purpose: Calculates compound interest while using dataflow objects. | ||
// | ||
// In this example, you supply the program with the principal [$], the interest | ||
// rate [%], the length of the compound period [months], and the length of time | ||
// the money is invested [months]. The program will calculate the new total | ||
// amount of money you have and the amount of interest made. For example if | ||
// you have $100, an interest rate of 5%, a compound period of 6 months and | ||
// you leave your money in that account for 36 months you will end up with | ||
// $134.01 and will have made $34.01 in interest. | ||
/////////////////////////////////////////////////////////////////////////////// | ||
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#include <hpx/hpx.hpp> | ||
#include <hpx/hpx_init.hpp> | ||
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#include <hpx/async_local/dataflow.hpp> | ||
#include <hpx/modules/actions_base.hpp> | ||
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#include <iostream> | ||
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using hpx::program_options::options_description; | ||
using hpx::program_options::value; | ||
using hpx::program_options::variables_map; | ||
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/////////////////////////////////////////////////////////////////////////////// | ||
//[interest_calc_add_action | ||
// Calculate interest for one period | ||
double calc(double principal, double rate) | ||
{ | ||
return principal * rate; | ||
} | ||
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/////////////////////////////////////////////////////////////////////////////// | ||
// Add the amount made to the principal | ||
double add(double principal, double interest) | ||
{ | ||
return principal + interest; | ||
} | ||
//] | ||
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/////////////////////////////////////////////////////////////////////////////// | ||
//[interest_hpx_main | ||
int hpx_main(variables_map& vm) | ||
{ | ||
{ | ||
using hpx::dataflow; | ||
using hpx::make_ready_future; | ||
using hpx::shared_future; | ||
using hpx::unwrapping; | ||
hpx::id_type here = hpx::find_here(); | ||
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double init_principal = | ||
vm["principal"].as<double>(); //Initial principal | ||
double init_rate = vm["rate"].as<double>(); //Interest rate | ||
int cp = vm["cp"].as<int>(); //Length of a compound period | ||
int t = vm["time"].as<int>(); //Length of time money is invested | ||
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init_rate /= 100; //Rate is a % and must be converted | ||
t /= cp; //Determine how many times to iterate interest calculation: | ||
//How many full compound periods can fit in the time invested | ||
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// In non-dataflow terms the implemented algorithm would look like: | ||
// | ||
// int t = 5; // number of time periods to use | ||
// double principal = init_principal; | ||
// double rate = init_rate; | ||
// | ||
// for (int i = 0; i < t; ++i) | ||
// { | ||
// double interest = calc(principal, rate); | ||
// principal = add(principal, interest); | ||
// } | ||
// | ||
// Please note the similarity with the code below! | ||
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shared_future<double> principal = make_ready_future(init_principal); | ||
shared_future<double> rate = make_ready_future(init_rate); | ||
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for (int i = 0; i < t; ++i) | ||
{ | ||
shared_future<double> interest = | ||
dataflow(unwrapping(calc), principal, rate); | ||
principal = dataflow(unwrapping(add), principal, interest); | ||
} | ||
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// wait for the dataflow execution graph to be finished calculating our | ||
// overall interest | ||
double result = principal.get(); | ||
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std::cout << "Final amount: " << result << std::endl; | ||
std::cout << "Amount made: " << result - init_principal << std::endl; | ||
} | ||
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return hpx::finalize(); | ||
} | ||
//] | ||
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/////////////////////////////////////////////////////////////////////////////// | ||
//[interest_main | ||
int main(int argc, char** argv) | ||
{ | ||
options_description cmdline("Usage: " HPX_APPLICATION_STRING " [options]"); | ||
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cmdline.add_options()("principal", value<double>()->default_value(1000), | ||
"The principal [$]")("rate", value<double>()->default_value(7), | ||
"The interest rate [%]")("cp", value<int>()->default_value(12), | ||
"The compound period [months]")("time", | ||
value<int>()->default_value(12 * 30), | ||
"The time money is invested [months]"); | ||
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hpx::init_params init_args; | ||
init_args.desc_cmdline = cmdline; | ||
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return hpx::init(argc, argv, init_args); | ||
} | ||
//] |
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