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Update 10.1 斐波那契数列.md #1213

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16 changes: 16 additions & 0 deletions notes/10.1 斐波那契数列.md
Original file line number Diff line number Diff line change
Expand Up @@ -31,6 +31,22 @@ public int Fibonacci(int n) {
return fib[n];
}
```
OR Simplified code
class FibonacciExample1{
public static void main(String args[])
{
int n1=0,n2=1,n3,i,count=10;
System.out.print(n1+" "+n2);//printing 0 and 1

for(i=2;i<count;++i)//loop starts from 2 because 0 and 1 are already printed
{
n3=n1+n2;
System.out.print(" "+n3);
n1=n2;
n2=n3;
}

}}

考虑到第 i 项只与第 i-1 和第 i-2 项有关,因此只需要存储前两项的值就能求解第 i 项,从而将空间复杂度由 O(N) 降低为 O(1)。

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