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London | March-2025 | Elhadj Abdoul Diallo | improve_with_precomputing #19

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Original file line number Diff line number Diff line change
Expand Up @@ -7,12 +7,15 @@ def find_longest_common_prefix(strings: List[str]):

In the event that an empty list, a list containing one string, or a list of strings with no common prefixes is passed, the empty string will be returned.
"""
if len(strings) < 2:
return ""
# Precompute: sort the strings so common prefixes are adjacent
sorted_strings = sorted(strings)
longest = ""
for string_index, string in enumerate(strings):
for other_string in strings[string_index+1:]:
common = find_common_prefix(string, other_string)
if len(common) > len(longest):
longest = common
for i in range(len(sorted_strings) - 1):
common = find_common_prefix(sorted_strings[i], sorted_strings[i + 1])
if len(common) > len(longest):
longest = common
return longest


Expand Down
Original file line number Diff line number Diff line change
Expand Up @@ -2,13 +2,9 @@ def count_letters(s: str) -> int:
"""
count_letters returns the number of letters which only occur in upper case in the passed string.
"""
only_upper = set()
for letter in s:
if is_upper_case(letter):
if letter.lower() not in s:
only_upper.add(letter)
# Precompute all lowercase and uppercase letters in the string
lower_set = set(c for c in s if c.islower())
upper_set = set(c for c in s if c.isupper())
# Only count uppercase letters that do not have a lowercase version in the string
only_upper = {c for c in upper_set if c.lower() not in lower_set}
return len(only_upper)


def is_upper_case(letter: str) -> bool:
return letter == letter.upper()