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jk0527
reviewed
Sep 15, 2022
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| cout << "<"; | ||
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| while (!q.empty()) |
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연산을 하는 부분은 함수화해도 좋을 것 같아요. 함수에서 vector에 원소를 순서대로 저장하고
vector를 main에서 받아서 한 번에 출력하면 어떨까요?
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| if(!q.empty()) | ||
| cout << ", "; |
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< , >를 사이사이에 출력해야 해서 출력 조건이 조금 복잡하게 들어갔네요..! 앞서 말씀드린 것처럼 vector에 저장한 후에 출력하면 좀 더 코드가 깔끔해질 것 같아요!!
junghk0115
reviewed
Sep 15, 2022
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| for (int i = n - 1; i >= 0; i--) { | ||
| if (arr[i] == 1) { | ||
| //맨 뒤에 push | ||
| deq.push_back(card); | ||
| } | ||
| else if (arr[i] == 2) { | ||
| int end = deq.back(); | ||
| deq.pop_back(); | ||
| //맨 뒤에서 두번째에 push | ||
| deq.push_back(card); | ||
| deq.push_back(end); | ||
| } | ||
| else if (arr[i] == 3) { | ||
| //맨 앞에 push | ||
| deq.push_front(card); | ||
| } | ||
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| //순서대로 1,2, ..., N. | ||
| card++; | ||
| } |
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p2. 해당 부분은 문제 풀이의 핵심 부분이니 함수화 하시는 것을 권장드립니다!
참고로 코딩테스트에선 대부분 main이 제공되지 않고 solution 함수만 제공되어 정답을 리턴하는 형태이니 함수화에 익숙해지시면 좋을 것 같습니다!
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내용 & 질문
스택, 큐, 덱 과제 제출합니다!
<기존 제출>
문제 번호 11866, 18115
<추가 제출>