Do we need n? (#13)

* don't need to assign self.__n_x_nodes until __call__

* more consistent use of single element slice

flexknot/priors.py

@@ -65,7 +65,6 @@ def __init__(self, x_min, x_max, y_min, y_max, N_min, N_max):
         # redefine self._x_prior
         self.__used_x_prior = self._x_prior
         self.__unused_x_prior = UniformPrior(x_min, x_max)
-        self.__n_x_nodes = int(N_max)
         self._x_prior = (
             lambda hypercube_x: np.concatenate(
                 (
@@ -88,7 +87,7 @@ def __call__(self, hypercube):
 
         """
         prior = np.empty(hypercube.shape)
-        prior[[0]] = self._N_prior(hypercube[0:1])
+        prior[[0]] = self._N_prior(hypercube[[0]])
         self.__n_x_nodes = int(prior[0])
         prior[1:] = super().__call__(hypercube[1:])
         return prior

pyproject.toml

@@ -1,6 +1,6 @@
 [project]
 name = "flexknot"
-version = "1.2.0"
+version = "1.2.1"
 description = "Flex-Knot"
 authors = [{name="Adam Neil Ormondroyd", email="[email protected]"}]
 readme = "README.md"