将两个有序链表合并为一个新的有序链表并返回。新链表是通过拼接给定的两个链表的所有节点组成的。
输入:1->2->4, 1->3->4
输出:1->1->2->3->4->4
迭代
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
ListNode dummy = new ListNode(0);
ListNode head = dummy;
while (l1 != null || l2 != null) {
if (l1 == null) {
head.next = new ListNode(l2.val);
l2 = l2.next;
} else if (l2 == null) {
head.next = new ListNode(l1.val);
l1 = l1.next;
} else {
if (l1.val >= l2.val){
head.next = new ListNode(l2.val);
l2 = l2.next;
} else {
head.next = new ListNode(l1.val);
l1 = l1.next;
}
}
head = head.next;
}
return dummy.next;
}
}
递归
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
if (l1 == null) return l2;
if (l2 == null) return l1;
if (l1.val < l2.val){
l1.next = mergeTwoLists(l1.next, l2);
return l1;
} else {
l2.next = mergeTwoLists(l1, l2.next);
return l2;
}
}
}