Not valid URL

[ThunderSon]

Hello. I have specified a certain website, but with a port, e.g. https://example.org:5541/index/ and it resulted in an error specifying that this is not a valid URL.

[shahriar0247]

yeah that happens a lot

[shahriar0247]

do one thing, change (in scan.py)

 if "?" in url:
		 	rce_func(url)
		 	xss_func(url)
		 	error_based_sqli_func(url)
		 else:
			print ga.red +"\n [Warning] "+ ga.end + ga.bold+"%s"%url +ga.end + ga.red +" is not a valid URL"+ga.end			
			print ga.red +" [Warning] You should write a Full URL .e.g http://site.com/page.php?id=value \n"+ ga.end
			exit()   

to

  if 1 == 1:
                        rce_func(url)
                        xss_func(url)
                        error_based_sqli_func(url)

[zigoo0]

Hi, the problem is not about ports, it is about missing parameters in url. when this tool was created, the purpose was to quickly scan large set of urls with parameters in order to quickly identify vulnerabilities. It is not meant to be a full web application scanner that you point it to a folder or domain and starts scanning.
Thank you.