Code Testcase Testcase Result 197. Rising Temperature

SELECT t1.id
FROM weather as t1
INNER JOIN weather as t2
ON to_days(t1.recordDate)  = to_days(t2.recordDate) +1  
WHERE t1.temperature > t2.temperature;

-----
SELECT w1.id
FROM Weather AS w1 , Weather AS w2
WHERE w1.Temperature > w2.Temperature AND DATEDIFF(w1.recordDate , w2.recordDate) = 1


Table: Weather

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| recordDate    | date    |
| temperature   | int     |
+---------------+---------+
id is the column with unique values for this table.
This table contains information about the temperature on a certain day.
 

Write a solution to find all dates' Id with higher temperatures compared to its previous dates (yesterday).

Return the result table in any order.

The result format is in the following example.

 

Example 1:

Input: 
Weather table:
+----+------------+-------------+
| id | recordDate | temperature |
+----+------------+-------------+
| 1  | 2015-01-01 | 10          |
| 2  | 2015-01-02 | 25          |
| 3  | 2015-01-03 | 20          |
| 4  | 2015-01-04 | 30          |
+----+------------+-------------+
Output: 
+----+
| id |
+----+
| 2  |
| 4  |
+----+
Explanation: 
In 2015-01-02, the temperature was higher than the previous day (10 -> 25).
In 2015-01-04, the temperature was higher than the previous day (20 -> 30).