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p095.c
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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* };
*/
/**
* Return an array of size *returnSize.
* Note: The returned array must be malloced, assume caller calls free().
*/
struct TreeNode **result;
int *min, *max, *indexofdepth, *left, *right, *val;
int resultsize;
void f(const int depth, const int index, const int n)
{
int i;
if (index == n)
{
struct TreeNode *node = (struct TreeNode*)malloc(sizeof(struct TreeNode)*n);
for (i = 0; i < n; i++)
{
node[i].val = val[i];
if (left[i] == -1) node[i].left = NULL;
else node[i].left = node+left[i];
if (right[i] == -1) node[i].right = NULL;
else node[i].right = node+right[i];
}
result[resultsize++] = node;
return;
}
int gotonextdepth = (index == indexofdepth[depth]);
if (depth > 0 && index == indexofdepth[depth-1]+1)
{
indexofdepth[depth+1] = indexofdepth[depth];
}
if (max[index] == min[index])
{
val[index] = min[index];
left[index] = right[index] = -1;
f(depth+gotonextdepth, index+1, n);
}
else
{
indexofdepth[depth+1]++;
min[indexofdepth[depth+1]] = min[index];
max[indexofdepth[depth+1]] = max[index]-1;
left[index] = indexofdepth[depth+1];
right[index] = -1;
val[index] = max[index];
f(depth+gotonextdepth, index+1, n);
min[indexofdepth[depth+1]] = min[index]+1;
max[indexofdepth[depth+1]] = max[index];
left[index] = -1;
right[index] = indexofdepth[depth+1];
val[index] = min[index];
f(depth+gotonextdepth, index+1, n);
if (max[index]-min[index] >= 2)
{
indexofdepth[depth+1]++;
for (i = min[index]+1; i <= max[index]-1; i++)
{
min[indexofdepth[depth+1]-1] = min[index];
max[indexofdepth[depth+1]-1] = i-1;
min[indexofdepth[depth+1]] = i+1;
max[indexofdepth[depth+1]] = max[index];
left[index] = indexofdepth[depth+1]-1;
right[index] = indexofdepth[depth+1];
val[index] = i;
f(depth+gotonextdepth, index+1, n);
}
indexofdepth[depth+1]--;
}
indexofdepth[depth+1]--;
}
}
struct TreeNode** generateTrees(int n, int* returnSize) {
if (n == 0)
{
(*returnSize) = 0;
return NULL;
}
resultsize = 0;
min = (int*)malloc(sizeof(int)*n);
max = (int*)malloc(sizeof(int)*n);
indexofdepth = (int*)malloc(sizeof(int)*n);
left = (int*)malloc(sizeof(int)*n);
right = (int*)malloc(sizeof(int)*n);
val = (int*)malloc(sizeof(int)*n);
result = (struct TreeNode**)malloc(sizeof(struct TreeNode*)*2000);
int i;
for (i = 0; i < n; i++)
{
indexofdepth[i] = 0;
left[i] = right[i] = -1;
}
min[0] = 1;
max[0] = n;
f(0, 0, n);
*returnSize = resultsize;
return result;
}