how to split UdpSocket?

[ta3pks]

UdpSocket used to have a split method which doesnt exist anymore, How does one split a udp socket at the moment?

[Darksonn]

This is explained in the documentation for UdpSocket.

This type does not provide a split method, because this functionality can be achieved by instead wrapping the socket in an Arc. Note that you do not need a Mutex to share the UdpSocket — an Arc<UdpSocket> is enough. This is because all of the methods take &self instead of &mut self. Once you have wrapped it in an Arc, you can call .clone() on the Arc<UdpSocket> to get multiple shared handles to the same socket. An example of such usage can be found further down.

There is also an example in the documentation:

use tokio::{net::UdpSocket, sync::mpsc};
use std::{io, net::SocketAddr, sync::Arc};

#[tokio::main]
async fn main() -> io::Result<()> {
    let sock = UdpSocket::bind("0.0.0.0:8080".parse::<SocketAddr>().unwrap()).await?;
    let r = Arc::new(sock);
    let s = r.clone();
    let (tx, mut rx) = mpsc::channel::<(Vec<u8>, SocketAddr)>(1_000);

    tokio::spawn(async move {
        while let Some((bytes, addr)) = rx.recv().await {
            let len = s.send_to(&bytes, &addr).await.unwrap();
            println!("{:?} bytes sent", len);
        }
    });

    let mut buf = [0; 1024];
    loop {
        let (len, addr) = r.recv_from(&mut buf).await?;
        println!("{:?} bytes received from {:?}", len, addr);
        tx.send((buf[..len].to_vec(), addr)).await.unwrap();
    }
}