Merge pull request #1 from okvarsh/okvarsh-patch-1

created DesignerPDFViewer.py

Author: okvarsh

Problem Solving/DesignerPDFViewer.py

@@ -0,0 +1,80 @@
+'''
+When a contiguous block of text is selected in a PDF viewer, the selection is highlighted with a blue rectangle. In this PDF viewer, each word is highlighted independently.
+
+There is a list of 26 character heights aligned by index to their letters. For example, 'a' is at index 0 and 'z' is at index 25. There will also be a string. Using the letter heights given, determine the area of the rectangle highlight in mm^2 assuming all letters are 1mm wide.
+
+Example
+h=[1,3,1,3,1,4,1,3,2,5,5,5,5,1,1,5,5,1,5,2,5,5,5,5,5,5]
+word='torn'
+The heights are t=2, o=1, r=1 and n=1. The tallest letter is 1 high and there are 4 letters. The hightlighted area will be 2*4=8mm^2 so the answer is 8.
+
+Function Description
+
+Complete the designerPdfViewer function in the editor below.
+
+designerPdfViewer has the following parameter(s):
+
+int h[26]: the heights of each letter
+string word: a string
+
+Returns
+
+int: the size of the highlighted area
+
+Input Format
+
+The first line contains  space-separated integers describing the respective heights of each consecutive lowercase English letter, ascii[a-z].
+The second line contains a single word consisting of lowercase English alphabetic letters.
+
+Constraints
+
+1<=h[?]<=7, where ? is an English lowercase letter.
+word contains no more than  letters.
+
+Sample input 0
+1 3 1 3 1 4 1 3 2 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5
+abc
+
+Sample output 0
+9
+
+Explanation 0
+We are highlighting the word abc:
+
+Letter heights are a=1, b=3 and c=1. The tallest letter, b, is 3mm high. The selection area for this word is 3*1*1=9mm^2.
+
+Note: Recall that the width of each character is 1mm.
+
+'''
+#!/bin/python3
+
+# Complete the designerPdfViewer function below.
+def designerPdfViewer(h, word):
+    ll=[]
+    for el in word:
+        ll.append(el)
+    print(ll)
+    asc=[]
+    for i in range(len(ll)):
+        print(ll[i]," ",ord(ll[i]))
+        asc.append(ord(ll[i])-97)
+    print(asc)
+    chval=[]
+    for elm in asc:
+        chval.append(h[elm])
+    print(chval)
+    return len(word)*max(chval)
+    
+    
+if __name__ == '__main__':
+    fptr = open(os.environ['OUTPUT_PATH'], 'w')
+
+    h = list(map(int, input().rstrip().split()))
+
+    word = input()
+
+    result = designerPdfViewer(h, word)
+
+    fptr.write(str(result) + '\n')
+
+    fptr.close()