Java Arraylist

/*Output Format
In each line, output the number located in  position of  line. If there is no such position, just print "ERROR!"

Sample Input

5
5 41 77 74 22 44
1 12
4 37 34 36 52
0
3 20 22 33
5
1 3
3 4
3 1
4 3
5 5
Sample Output

74
52
37
ERROR!
ERROR! */

code

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        String s = sc.nextLine();
        ArrayList<ArrayList<String>> a = new ArrayList<ArrayList<String>>(n);
        for (int i = 0; i < n; i++) {
            s = sc.nextLine();
            a.add(i, new ArrayList<String>(Arrays.asList(s.split("\\s"))));
        }

        int m = sc.nextInt();
        for (int i = 0; i < m; i++) {
            int x = sc.nextInt();
            int y = sc.nextInt();
            if (x <= a.size() && y < a.get(x-1).size() && y >= 0) {
                System.out.println(a.get(x-1).get(y));
            } else {
                System.out.println("ERROR!");
            }
        }
    }
}