Grouped cartesian product results support

[sekgobela-kevin]

Instead of having result of cartesian poduct as a very large iterator.
The result can be grouped by another iterable items which wil result in 3D iterable instead of 2D iterable.

prodius.product([0,1], [2,3]) -> [(0, 2), [0, 3), (1,2), (1,3)]

# First iterable was used for grouping
product.product_group([0,1], [2,3]) ->[[(0, 2), (0, 3)], [(1,2), (1,3)]] 

# Same thing be archieved as
product.product_group([2,3], group=[0,1]) ->[[(0, 2), (0, 3)], [(1,2), (1,3)]] 

[sekgobela-kevin]

Forcetable already has basic implementation of it.
But can be easily done using prodius.product() but individually on items of iterable with items for grouping.

product_group = []
for item in group:
  item_product = prodius.product([item], iterables)
  product_group.append(item_product)

[sekgobela-kevin]

There is no need to split functionality into its own function but let it be in form of argument.

product.product([2,3], group=[0,1]) ->[[(0, 2), (0, 3)], [(1,2), (1,3)]]