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102.二叉树的层序遍历.js
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102.二叉树的层序遍历.js
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/*
* @lc app=leetcode.cn id=102 lang=javascript
*
* [102] 二叉树的层序遍历
*
* https://leetcode-cn.com/problems/binary-tree-level-order-traversal/description/
*
* algorithms
* Medium (63.65%)
* Likes: 908
* Dislikes: 0
* Total Accepted: 330.6K
* Total Submissions: 515.5K
* Testcase Example: '[3,9,20,null,null,15,7]'
*
* 给你一个二叉树,请你返回其按 层序遍历 得到的节点值。 (即逐层地,从左到右访问所有节点)。
*
*
*
* 示例:
* 二叉树:[3,9,20,null,null,15,7],
*
*
* 3
* / \
* 9 20
* / \
* 15 7
*
*
* 返回其层序遍历结果:
*
*
* [
* [3],
* [9,20],
* [15,7]
* ]
*
*
*/
// @lc code=start
/**
* Definition for a binary tree node.
* function TreeNode(val, left, right) {
* this.val = (val===undefined ? 0 : val)
* this.left = (left===undefined ? null : left)
* this.right = (right===undefined ? null : right)
* }
*/
/**
* @param {TreeNode} root
* @return {number[][]}
*/
var levelOrder = function(root) {
// 深度优先遍历
const ret=[]
dfs(root,0,ret)
return ret
};
const dfs = (node, depth, arr) => {
if(!node) return
arr[depth] = arr[depth] || []
arr[depth].push(node.val)
dfs(node.left, depth+1, arr)
dfs(node.right, depth+1, arr)
}
// @lc code=end