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Provide methods to convert Tuple2 to Entry and Map. #597

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loggerhead opened this issue Feb 22, 2025 · 2 comments
Open

Provide methods to convert Tuple2 to Entry and Map. #597

loggerhead opened this issue Feb 22, 2025 · 2 comments

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@loggerhead
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Suppose there are two arrays, aa and bb. I want to convert them into a map in the form of {a: b}. Currently, I need to write the code like this:

aToB := lo.FromEntries(lo.Map(lo.Zip2(aa, bb), func(kv lo.Tuple2[int64, string], _ int) lo.Entry[int64, string] {
	return lo.Entry[int64, string]{
		Key:   kv.A,
		Value: kv.B,
	}
}))

It would be much more convenient if there were a method that could directly convert lo.Tuple2 to lo.Entry.

@samber
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samber commented Feb 22, 2025

First, i wonder if lo.Entry struct is still useful, since we now have lo.Tuple2.

As a soft breaking change, we could imagine the following helpers:

  • lo.ToPairs(a map) -> []tuple2
  • lo.FromPairs([]tuple2) -> a map

With such helpers, your example would be simply:

aToB := lo.FromPairs(lo.Zip2(aa, bb))

Until then, you can do something like:

lo.SliceToMap(lo.Zip2(aa, bb), func(t lo.Tuple2[K, V]) (K, V) {
  return t.A, t.B
})

[edit]: Sorry, lo.FromPairs and lo.ToPairs helpers already exist

@loggerhead
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It's great to replace lo.Entry with lo.Tuple2. They are kind of repetitive.

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