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[Bronze III] 1부터 차례로 나누면서 약수 개수를 카운트, K번째 약수를 찾으면 break
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수학/2501_약수구하기.cpp

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#include <iostream>
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using namespace std;
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int main () {
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int N, K;
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cin>>N>>K;
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int answer = 0;
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int divisorCnt = 0; // 약수 개수 카운트
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for (int i=1; i<=N; i++) {
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if (N%i == 0) {
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divisorCnt++;
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if (divisorCnt==K) {
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answer = i;
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break;
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}
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}
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}
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cout<<answer;
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}

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