|
| 1 | +/* |
| 2 | + |
| 3 | +Problem |
| 4 | + |
| 5 | + |
| 6 | +You will have to design a telephone directory where the following operations would be supported. |
| 7 | +1. GET: It will provide a number which is not assigned to anyone |
| 8 | +2. CHECK: Given a number it will tell whether it is assigned to anyone or not |
| 9 | +3. RELEASE: It will recycle or release a number |
| 10 | + |
| 11 | +*/ |
| 12 | + |
| 13 | +public class TelephoneDirectory |
| 14 | +{ |
| 15 | + public static void main(String[] args) |
| 16 | + { |
| 17 | + Directory directory = new Directory(5); |
| 18 | + int number1 = directory.getAvailableNumber(); |
| 19 | + System.out.println(number1); |
| 20 | + int number2 = directory.getAvailableNumber(); |
| 21 | + System.out.println(number2); |
| 22 | + System.out.println(directory.isAvailable(3)); |
| 23 | + int number3 = directory.getAvailableNumber(); |
| 24 | + System.out.println(number3); |
| 25 | + System.out.println(directory.isAvailable(3)); |
| 26 | + int number4 = directory.getAvailableNumber(); |
| 27 | + System.out.println(directory.isAvailable(3)); |
| 28 | + System.out.println(number4); |
| 29 | + int number5 = directory.getAvailableNumber(); |
| 30 | + System.out.println(number5); |
| 31 | + int number6 = directory.getAvailableNumber(); |
| 32 | + System.out.println(number6); |
| 33 | + int number7 = directory.getAvailableNumber(); |
| 34 | + System.out.println(number7); |
| 35 | + directory.release(3); |
| 36 | + System.out.println(directory.isAvailable(3)); |
| 37 | + int number8 = directory.getAvailableNumber(); |
| 38 | + System.out.println(number8); |
| 39 | + System.out.println(directory.isAvailable(3)); |
| 40 | + } |
| 41 | + |
| 42 | + private static class Directory |
| 43 | + { |
| 44 | + Node[] nodes; |
| 45 | + Node head; |
| 46 | + |
| 47 | + public Directory(int maxNumbers) |
| 48 | + { |
| 49 | + nodes = new Node[maxNumbers]; |
| 50 | + for (int i = 0; i < maxNumbers; ++i) |
| 51 | + { |
| 52 | + nodes[i] = new Node(i); |
| 53 | + if (i != 0) |
| 54 | + { |
| 55 | + nodes[i].previous = nodes[i - 1]; |
| 56 | + nodes[i - 1].next = nodes[i]; |
| 57 | + } |
| 58 | + } |
| 59 | + nodes[maxNumbers - 1].next = nodes[0]; |
| 60 | + nodes[0].previous = nodes[maxNumbers - 1]; |
| 61 | + head = nodes[0]; |
| 62 | + } |
| 63 | + |
| 64 | + public int getAvailableNumber() |
| 65 | + { |
| 66 | + if (head == null) |
| 67 | + return -1; |
| 68 | + int temp = head.number; |
| 69 | + head.available = false; |
| 70 | + if (head.next == head) |
| 71 | + head = null; |
| 72 | + else |
| 73 | + { |
| 74 | + head.previous.next = head.next; |
| 75 | + head.next.previous = head.previous; |
| 76 | + head = head.next; |
| 77 | + } |
| 78 | + return temp; |
| 79 | + } |
| 80 | + |
| 81 | + public boolean isAvailable(int number) |
| 82 | + { |
| 83 | + return nodes[number].available; |
| 84 | + } |
| 85 | + |
| 86 | + public void release(int number) |
| 87 | + { |
| 88 | + if (nodes[number].available == false) |
| 89 | + { |
| 90 | + nodes[number].available = true; |
| 91 | + if (head == null) |
| 92 | + { |
| 93 | + head = nodes[number]; |
| 94 | + nodes[number].next = nodes[number]; |
| 95 | + nodes[number].previous = nodes[number]; |
| 96 | + } else |
| 97 | + { |
| 98 | + nodes[number].next = head.next; |
| 99 | + nodes[number].previous = head; |
| 100 | + head.next.previous = nodes[number]; |
| 101 | + head.next = nodes[number]; |
| 102 | + } |
| 103 | + } |
| 104 | + } |
| 105 | + |
| 106 | + private static class Node |
| 107 | + { |
| 108 | + boolean available = true; |
| 109 | + Node next; |
| 110 | + Node previous; |
| 111 | + int number; |
| 112 | + |
| 113 | + public Node(int number) |
| 114 | + { |
| 115 | + this.number = number; |
| 116 | + } |
| 117 | + } |
| 118 | + } |
| 119 | + |
| 120 | +} |
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