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Borehole Constraints #71

Answered by mdtanker
geojoeyphillips asked this question in Q&A
May 20, 2024 · 1 comments · 13 replies
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Yes that would be great if you could test it! I have just implemented the fix in PR #74, which should be available now as v0.6.0 on pip, and should be on conda in the next day or 2.

This new version has several breaking changes, so make sure to look at the changelog to see how you'll need to update your code.

The gravity misfit is defined as misfit = observed - forward and misfit = region_misfit + residual_misfit. By setting the regional equal to the sampled misfit value at the borehole, you are setting regional_misfit = misfit (at the borehole) and therefore residual_misfit = 0 at the borehole. I hope this makes some sense.

Please ask me for more clarification if you need it, it's really…

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