Adding anagrams

Author: mamenesia

anagrams/anagram.js

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+// --- Directions
+// Check to see if two provided strings are anagrams of eachother.
+// One string is an anagram of another if it uses the same characters
+// in the same quantity. Only consider characters, not spaces
+// or punctuation.  Consider capital letters to be the same as lower case
+// --- Examples
+//   anagrams('rail safety', 'fairy tales') should return True
+//   anagrams('RAIL! SAFETY!', 'fairy tales') should return True
+//   anagrams('Hi there', 'Bye there') should return False
+
+// Solution No.1
+
+function anagrams(string1, string2) {
+  let charMap1 = buildCharMap(string1);
+  let charMap2 = buildCharMap(string2);
+
+  if(Object.keys(charMap1).length !== Object.keys(charMap2).length){
+    return false;
+  }
+
+  for (let char in charMap1) {
+    if(charMap1[char] !== charMap2[char]) {
+      return false;
+    }
+  }
+
+  return true;
+}
+
+function buildCharMap(str) {
+  let charMap = {};
+
+  for (let char of str.replace(/[^\w]/g, '').toLowerCase()) {
+    charMap[char] = charMap[char] + 1 || 1;
+  }
+
+  return charMap;
+}
+
+
+// Solution No. 2
+
+function anagrams(string1, string2) {
+  return cleanString(string1) === cleanString(string2);
+}
+
+function cleanString(str) {
+  return str.replace(/[^\w]/g, '').toLowerCase().split('').sort().join('');
+}

anagrams/directions.md

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+# --- Directions
+
+Check to see if two provided strings are anagrams of eachother.
+One string is an anagram of another if it uses the same characters
+in the same quantity. Only consider characters, not spaces
+or punctuation.  Consider capital letters to be the same as lower case
+
+# --- Examples
+  * anagrams('rail safety', 'fairy tales') should return True
+  * anagrams('RAIL! SAFETY!', 'fairy tales') should return True
+  * anagrams('Hi there', 'Bye there') should return False
+
+
+# --- Solution
+
+Solution No 1
+
+    function anagrams(string1, string2) {
+      let charMap1 = buildCharMap(string1);
+      let charMap2 = buildCharMap(string2);
+
+      if(Object.keys(charMap1).length !== Object.keys(charMap2).length){
+        return false;
+      }
+
+      for (let char in charMap1) {
+        if(charMap1[char] !== charMap2[char]) {
+          return false;
+        }
+      }
+
+      return true;
+    }
+
+    function buildCharMap(str) {
+      let charMap = {};
+
+      for (let char of str.replace(/[^\w]/g, '').toLowerCase()) {
+        charMap[char] = charMap[char] + 1 || 1;
+      }
+
+      return charMap;
+    }
+
+
+Solution No. 2
+
+    function anagrams(string1, string2) {
+      return cleanString(string1) === cleanString(string2);
+    }
+
+    function cleanString(str) {
+      return str.replace(/[^\w]/g, '').toLowerCase().split('').sort().join('');
+    }