-
Notifications
You must be signed in to change notification settings - Fork 0
/
328. Odd Even Linked List
60 lines (50 loc) · 1.58 KB
/
328. Odd Even Linked List
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
/*
Given a singly linked list, group all odd nodes together followed by the even nodes.
Please note here we are talking about the node number and not the value in the nodes.
You should try to do it in place. The program should run in O(1) space complexity and O(nodes) time complexity.
Example 1:
Input: 1->2->3->4->5->NULL
Output: 1->3->5->2->4->NULL
Example 2:
Input: 2->1->3->5->6->4->7->NULL
Output: 2->3->6->7->1->5->4->NULL
Note:
-The relative order inside both the even and odd groups should remain as it was in the input.
-The first node is considered odd, the second node even and so on ...
*/
/*
Idea: iterate through list and create 2 separate lists: odds and evens, then merge odds tail with evens head;
*/
class Solution {
public ListNode oddEvenList(ListNode head) {
if (head == null || head.next == null) {
return head;
}
ListNode curr = head.next.next;
ListNode oddsHead = head;
ListNode evensHead = head.next;
ListNode odds = oddsHead;
ListNode evens = evensHead;
while (curr != null) {
if(odds != null) {
odds.next = curr;
odds = odds.next;
}
if(evens != null) {
evens.next = curr.next;
evens = evens.next;
}
curr = curr.next != null ? curr.next.next : null;
}
odds.next = evensHead;
return oddsHead;
}
}
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/