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Since all the elements in Q is distinct, we would go into this if statement
only once, so there is no need and will never update a existed value res twice.
Original issue reported on code.google.com by [email protected] on 21 Apr 2013 at 8:44
I am not so sure about this one since although all elements in Q are distinct,
we may have duplicate elements in A such that we may update D.back() which
means we need to check that.
Original issue reported on code.google.com by
[email protected]
on 21 Apr 2013 at 8:44Attachments:
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