Feat: Support variant and continue

[Seidko]

I found that content_type has three types when I was analyzing the API: next variant and continue. Chatgpt plugin currently implements next type, and the variant type allows the AI to change the way it says, while the continue type completes a truncated sentence. Now I want to implement these two types in chatgpt plugin.

[MaikoTan]

Looks like #18 can be solved with continue as well.

[Seidko]

Which means. I can implement continue by merging the parts of the conversation?

[MaikoTan]

No, I mean you could implement continue then the problem in #18 would be solved, so we don't need to do the merge-whatever things.

[Seidko]

Got it. I will start working on it now.

[Seidko]

Because I need to implement continue and variant, I need to save the previous message. Do you have any different ideas?

[MaikoTan]

There was a parent message id that I have processed already. Is there any problem with it?

chatgpt-bot/src/api.ts

Line 15 in 38354f1

message: string

chatgpt-bot/src/api.ts

Line 68 in 38354f1

parent_message_id: messageId,

chatgpt-bot/src/api.ts

Line 119 in 38354f1

messageId = message?.id

[Seidko]

No, actually the conversations saved in koishi only has messageId and conversationId, so I came to ask this question.

chatgpt-bot/src/index.ts

Line 40 in e6adbcf

const conversations = new Map<string, { messageId: string; conversationId: string }>()

[Seidko]

I need to save the previous message for chatgpt in order to implement variant and continue.

[MaikoTan]

I don't really know what is variant and continue even though you mentioned them several times. Would you mind explaining what are and how they would behave in the conversation? Merci.

[Seidko]

Sure. The purpose of variant is to let the AI regenerate the previous sentence, which is equivalent to the Try again button in the ChatGPT web page. I haven't tested the function of continue, but according to the name, it should be to continue the truncated part.

[Seidko]

I just successfully tested the function of continue, but I'm not sure if it is really the function of continue.