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compressTheString.java
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compressTheString.java
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/*
Write a program to do basic string compression. For a character which is consecutively repeated more than once, replace consecutive duplicate occurrences with the count of repetitions.
Example:
If a string has 'x' repeated 5 times, replace this "xxxxx" with "x5".
The string is compressed only when the repeated character count is more than 1.
Note:
Consecutive count of every character in the input string is less than or equal to 9.
Input Format:
The first and only line of input contains a string without any leading and trailing spaces.
Output Format:
The output contains the string after compression printed in single line.
Note:
You are not required to print anything. It has already been taken care of. Just implement the given function.
Constraints:
0 <= N <= 10^6
Where 'N' is the length of the input string.
Time Limit: 1 sec
Sample Input 1:
aaabbccdsa
Sample Output 1:
a3b2c2dsa
Explanation for Sample Output 1:
In the given string 'a' is repeated 3 times, 'b' is repeated 2 times, 'c' is repeated 2 times and 'd', 's' and 'a' and occuring 1 time hence no compression for last 3 characters.
Sample Input 2:
aaabbcddeeeee
Sample Output 2:
a3b2cd2e5
Explanation for Sample Output 2:
In the given string 'a' is repeated 3 times, 'b' is repeated 2 times, 'c' is occuring single time, 'd' is repeating 2 times and 'e' is repeating 5times.
*/
public class Solution
{
public static String getCompressedString(String str) {
// Write your code here.
String words = "";
if(str.length() == 0)
{
return "";
}
else
{
char check = str.charAt(0);
int count = 0;
for(int i = 0; i < str.length(); i++)
{
if(str.charAt(i) == check)
{
count++;
}
else if(str.charAt(i) != check)
{
if(count > 1)
{
words += Character.toString(check) + (count);
}
else
words += Character.toString(check);
check = str.charAt(i);
count = 1;
}
}
if(count > 1)
{
words += Character.toString(check) + (count);
}
else
words += Character.toString(check);
}
return words;
}
}