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Edited ch01.asciidoc with Atlas code editor
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@@ -601,7 +601,7 @@ We can then multiply every element in both sets to get this equality:
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The left side is the same as `(p-1)! % p` where `!` is the factorial (e.g.,
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`5! = 5 ⋅ 432 ⋅ 1`). On the right side, we can gather up all the `n`'s and get:
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`5! = 5``4``3``2``1`). On the right side, we can gather up all the `n`'s and get:
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