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Copy pathCount Salary Categories
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Count Salary Categories
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** Count Salary Categories **
Table: Accounts
+-------------+------+
| Column Name | Type |
+-------------+------+
| account_id | int |
| income | int |
+-------------+------+
account_id is the primary key (column with unique values) for this table.
Each row contains information about the monthly income for one bank account.
Write a solution to calculate the number of bank accounts for each salary category. The salary categories are:
"Low Salary": All the salaries strictly less than $20000.
"Average Salary": All the salaries in the inclusive range [$20000, $50000].
"High Salary": All the salaries strictly greater than $50000.
The result table must contain all three categories. If there are no accounts in a category, return 0.
Return the result table in any order.
The result format is in the following example.
Example 1:
Input:
Accounts table:
+------------+--------+
| account_id | income |
+------------+--------+
| 3 | 108939 |
| 2 | 12747 |
| 8 | 87709 |
| 6 | 91796 |
+------------+--------+
Output:
+----------------+----------------+
| category | accounts_count |
+----------------+----------------+
| Low Salary | 1 |
| Average Salary | 0 |
| High Salary | 3 |
+----------------+----------------+
Explanation:
Low Salary: Account 2.
Average Salary: No accounts.
High Salary: Accounts 3, 6, and 8.
Solution
SELECT
'Low Salary' AS category,
SUM(CASE WHEN income < 20000 THEN 1 ELSE 0 END) AS accounts_count
FROM
Accounts
UNION
SELECT
'Average Salary' category,
SUM(CASE WHEN income >= 20000 AND income <= 50000 THEN 1 ELSE 0 END)
AS accounts_count
FROM
Accounts
UNION
SELECT
'High Salary' category,
SUM(CASE WHEN income > 50000 THEN 1 ELSE 0 END) AS accounts_count
FROM
Accounts