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merge_sort.c
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merge_sort.c
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/*
* Date: 2018-09-09
*
* Description:
* Implement merge sort.
*
* Approach:
* Partitions array in equal half and merges them back again in sorted order.
* This is done recursively until all array elements are sorted.
*
* Complexity:
* Time - O(nlogn)
* Space - O(n)
*/
#include "stdio.h"
#include "stdlib.h"
void merge(int a[], int l, int m, int r) {
int i = 0, j = 0, k = l;
int n1 = m - l + 1;
int n2 = r - m;
int *L = (int *)malloc(sizeof(int)*n1);
int *R = (int *)malloc(sizeof(int)*n2);
for (i = 0; i < n1; i++)
L[i] = a[l + i];
for (j = 0; j < n2; j++)
R[j] = a[m + 1 + j];
i = 0;
j = 0;
k = l;
while ((i < n1) && (j < n2)) {
if (L[i] < R[j]) {
a[k] = L[i];
i++;
}
else {
a[k] = R[j];
j++;
}
k++;
}
while (i < n1) {
a[k] = L[i];
k++;
i++;
}
while (j < n2) {
a[k] = R[j];
k++;
j++;
}
free(L);
free(R);
}
/*
* If number of elements in array is 2 like [2, 1] this function does not sort
* these 2 elements, we can handle this special case separately.
*/
void mergeSort(int a[], int l, int r) {
int m = 0;
if (l < r) {
m = l + (r - l)/2;
mergeSort(a, l, m);
mergeSort(a, m + 1, r);
merge(a, l, m, r);
}
}
int main() {
int i = 0;
int n = 0;
int *a = NULL;
printf("Enter number of elements: ");
scanf("%d",&n);
a = (int *)malloc(sizeof(int)*n);
for (i = 0; i < n; i++) {
printf("Enter element [%d]: ", i);
scanf("%d",&a[i]);
}
mergeSort(a, 0, n - 1);
printf("Sorted array elements: \n");
for (i = 0; i < n; i++)
printf("a[%d]: %d\n", i, a[i]);
return 0;
}