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9.14 Correction #13

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kunliu7 opened this issue Mar 10, 2021 · 0 comments

kunliu7 commented Mar 10, 2021

In the box,

This is wrong. A positive operator makes sure that it has non-negative eigenvalues.

When performing $\sqrt A$, you need to sqrt the eigenvalues under the expression of spectral decomposition:

$$ \sqrt A = \sum_i \sqrt \lambda_i | i \rangle \langle i | $$

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