How can I set creds and stroage aliases

[Cnily03]

I have read the documentation but cannot find a valid way to route some emails to one specific account (credential)

How can I implement such functions:

• alias [email protected] and [email protected] to cred user

• alias [email protected] and [email protected] to imapsql user

As I login as [email protected] or [email protected], the account info are same and the table is user

And the IMAP storage of [email protected] and [email protected] are same storaged in table user

[foxcpp]

https://maddy.email/multiple-domains/

[Cnily03]

I mean something more complicated.
[email protected] and [email protected] are linked to the same account and map. But [email protected] and [email protected] don't make alais.

[foxcpp]

Any module under "Lookup tables" can be used for auth_map/storage_map/delivery_map.
Take a look at https://maddy.email/reference/table/static, https://maddy.email/reference/table/chain/ in particular.

E.g. how your example in original post could be implemented:

table.chain accounts_map {
  optional_step static {
    entry [email protected] user
    entry [email protected] user
  }
  step identity # default, ccc@* -> ccc@*
}

# Use it everywhere.
submission ... {
  auth_map &accounts_map
}
imap ... {
  auth_map &accounts_map
  storage_map &accounts_map
}
storage.imapsq local_storage {
  delivery_map &accounts_map
}

[stellarpower]

Is it also possible to chain for authentication providers? I have two separate ways to authenticate users:

auth.pass_table authentication_one {
    ...
}

auth.pass_table authentication_two {
    ...
}

imap tls://0.0.0.0:4993 tcp://0.0.0.0:4143 {
    auth &authentication_one
    auth &authentication_two
}

I'd like to combine them into one module I can refer to just once, e.g.:

table.chain registered_user {
    auth.pass_table authentication_one {
        ...
    }
    
    auth.pass_table authentication_two {
        ...
    }
}

imap tls://0.0.0.0:4993 tcp://0.0.0.0:4143 {
    auth &registered_user
}

Tried a couple of permutations but no luck so far, is thi possible?
Thanks