Prompt only if --option's argument isn't provided

[yozachar]

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Example Code

import typer


cli = typer.Typer()


@cli.command()
def req(
    username: str = 'admin',
    password: str = typer.Option(
        'default',
        prompt=typer.prompt('Password'), # True,
        # prompt_required=True,
    )
) -> None:
    print(f'Username: {username} | Password: {password}')

cli()

Description

• Assume that the above code runs directly with command req

• I would prefer if it were possible to provide password via prompt and not on commandline

• Additionlly, using getpass & getuser seems more favourable.

• When I provide a command like:

  $ req --username myuser --password

  It prompts, but afterword it runs into error:

  Password:
  Error: Option '--password,' requires an argument

Wanted Solution

Prompt for (here) password only when --password is passed w/o any argument.

Wanted Code

# NAY

Alternatives

NA

Operating System

Linux

Operating System Details

Arch Linux
Kernel: 5.18

Typer Version

0.6.1

Python Version

3.10.5

Additional Context

No response

[yozachar]

My bad, I do not understand this behavior:

~/test via 🐍 v3.10.5 (test)
➜ python -m test_typer --password "def"
Password: abc # why prompt at all?
Username: admin | Password: def

~/test via 🐍 v3.10.5 (test)
➜ python -m test_typer
Password: def
def [default]: 123 # why? what's this?!
Username: admin | Password: 123

~/test via 🐍 v3.10.5 (test) 
➜ python -m test_typer --password      
Password: 123 # why not read from here?
Error: Option '--password' requires an argument

Can someone please explain?

[osintalex]

I think something like this could give you what you want to achieve, if I've understood correctly. Instead of specifying the --password option and leaving it blank, you just don't use that option at all.

import typer


def main(
    user: str,
    password: str = typer.Option("", help="Enter your password."),
):
    if password:
        print(f"{user} and {password}")
    else:
        new_password = typer.prompt("Enter your password", confirmation_prompt=True, hide_input=True)
        print(f"user is: {user} and password is: {new_password}")


if __name__ == "__main__":
    typer.run(main)

As far as I can tell, if you add an option, then use the option when you are running the program on the command line, you have to specify some value for that option - i.e. there is no way to leave it blank. So I don't think the way you're trying to solve this is possible.

[yozachar]

Yup, I've done something like this.

... if you add an option, then use the option when you are running the program on the command line, you have to specify some value for that option ...

Right, but it feels counter intuitive when used with prompt

[heiskane]

prompt actually takes in a boolean so i believe that what you actually want it:

import typer

cli = typer.Typer()


@cli.command()
def req(
    username: str = "admin",
    password: str = typer.Option("default", prompt=True),
) -> None:
    print(f"Username: {username} | Password: {password}")

cli()

Output:

$ python /tmp/asd/potato/potato/main.py
Password [default]: hello
Username: admin | Password: hello

[yozachar]

Thanks @heiskane!