-
Notifications
You must be signed in to change notification settings - Fork 47
/
bst.py
229 lines (199 loc) · 7.29 KB
/
bst.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
# # # Binary search tree
class binarySearchTree:
def __init__(self,val=None):
self.val = val
self.left = None
self.right = None
def insert(self,val):
# check if there is no root
if (self.val == None):
self.val = val
# check where to insert
else:
# check for duplicate then stop and return
if val == self.val: return 'no duplicates aloowed in binary search tree'
# check if value to be inserted < currentNode's value
if (val < self.val):
# check if there is a left node to currentNode if true then recurse
if(self.left):
self.left.insert(val)
# insert where left of currentNode when currentNode.left=None
else: self.left = binarySearchTree(val)
# same steps as above here the condition we check is value to be inserted > currentNode's value
else:
if(self.right):
self.right.insert(val)
else: self.right = binarySearchTree(val)
def breadthFirstSearch(self):
currentNode = self
bfs_list = []
queue = []
queue.insert(0,currentNode)
while(len(queue) > 0):
currentNode = queue.pop()
bfs_list.append(currentNode.val)
if(currentNode.left):
queue.insert(0,currentNode.left)
if(currentNode.right):
queue.insert(0,currentNode.right)
return bfs_list
# In order means first left child, then parent, at last right child
def depthFirstSearch_INorder(self):
return self.traverseInOrder([])
# Pre order means first parent, then left child, at last right child
def depthFirstSearch_PREorder(self):
return self.traversePreOrder([])
# Post order means first left child, then right child , at last parent
def depthFirstSearch_POSTorder(self):
return self.traversePostOrder([])
def traverseInOrder(self, lst):
if (self.left):
self.left.traverseInOrder(lst)
lst.append(self.val)
if (self.right):
self.right.traverseInOrder(lst)
return lst
def traversePreOrder(self, lst):
lst.append(self.val)
if (self.left):
self.left.traversePreOrder(lst)
if (self.right):
self.right.traversePreOrder(lst)
return lst
def traversePostOrder(self, lst):
if (self.left):
self.left.traversePostOrder(lst)
if (self.right):
self.right.traversePostOrder(lst)
lst.append(self.val)
return lst
def findNodeAndItsParent(self,val, parent = None):
# returning the node and its parent so we can delete the node and reconstruct the tree from its parent
if val == self.val: return self, parent
if (val < self.val):
if (self.left):
return self.left.findNodeAndItsParent(val, self)
else: return 'Not found'
else:
if (self.right):
return self.right.findNodeAndItsParent(val, self)
else: return 'Not found'
# deleteing a node means we have to rearrange some part of the tree
def delete(self,val):
# check if the value we want to delete is in the tree
if(self.findNodeAndItsParent(val)=='Not found'): return 'Node is not in tree'
# we get the node we want to delete and its parent-node from findNodeAndItsParent method
deleteing_node, parent_node = self.findNodeAndItsParent(val)
# check how many children nodes does the node we are going to delete have by traversePreOrder from the deleteing_node
nodes_effected = deleteing_node.traversePreOrder([])
# if len(nodes_effected)==1 means, the node to be deleted doesn't have any children
# so we can just check from its parent node the position(left or right) of node we want to delete
# and point the position to 'None' i.e node is deleted
if (len(nodes_effected)==1):
if (parent_node.left.val == deleteing_node.val) : parent_node.left = None
else: parent_node.right = None
return 'Succesfully deleted'
# if len(nodes_effected) > 1 which means the node we are going to delete has 'children',
# so the tree must be rearranged from the deleteing_node
else:
# if the node we want to delete doesn't have any parent means the node to be deleted is 'root' node
if (parent_node == None):
nodes_effected.remove(deleteing_node.val)
# make the 'root' nodee i.e self value,left,right to None,
# this means we need to implement a new tree again without the delted node
self.left = None
self.right = None
self.val = None
# construction of new tree
for node in nodes_effected:
self.insert(node)
return 'Succesfully deleted'
# if the node we want to delete has a parent
# traverse from parent_node
nodes_effected = parent_node.traversePreOrder([])
# deleting the node
if (parent_node.left == deleteing_node) : parent_node.left = None
else: parent_node.right = None
# removeing the parent_node, deleteing_node and inserting the nodes_effected in the tree
nodes_effected.remove(deleteing_node.val)
nodes_effected.remove(parent_node.val)
for node in nodes_effected:
self.insert(node)
return 'Successfully deleted'
bst = binarySearchTree()
bst.insert(7)
bst.insert(4)
bst.insert(9)
bst.insert(0)
bst.insert(5)
bst.insert(8)
bst.insert(13)
# 7
# / \
# / \
# 4 9
# / \ / \
# 0 5 8 13
print('IN order: ',bst.depthFirstSearch_INorder()) # useful in sorting the tree in ascending order
print('PRE order:' ,bst.depthFirstSearch_PREorder()) # pre order is useful in reconstructing a tree
print('POST order:', bst.depthFirstSearch_POSTorder()) # useful in finding the leaf nodes
print(bst.delete(5))
print(bst.delete(9))
print(bst.delete(7))
# after deleting
print('IN order: ',bst.depthFirstSearch_INorder())
"""
Another Implementation
"""
class GFG :
@staticmethod
def main( args) :
tree = BST()
tree.insert(30)
tree.insert(50)
tree.insert(15)
tree.insert(20)
tree.insert(10)
tree.insert(40)
tree.insert(60)
tree.inorder()
class Node :
left = None
val = 0
right = None
def __init__(self, val) :
self.val = val
class BST :
root = None
def insert(self, key) :
node = Node(key)
if (self.root == None) :
self.root = node
return
prev = None
temp = self.root
while (temp != None) :
if (temp.val > key) :
prev = temp
temp = temp.left
elif(temp.val < key) :
prev = temp
temp = temp.right
if (prev.val > key) :
prev.left = node
else :
prev.right = node
def inorder(self) :
temp = self.root
stack = []
while (temp != None or not (len(stack) == 0)) :
if (temp != None) :
stack.append(temp)
temp = temp.left
else :
temp = stack.pop()
print(str(temp.val) + " ", end ="")
temp = temp.right
if __name__=="__main__":
GFG.main([])
# This code is contributed by rastogik346.