set_union.py

"""

Problem Statement

AuB.png.union()

.union() operator returns the union of set and the set of elements in an iterable. 
Sometimes '|' operator is used in place of .union() operator but it operates only on the set of elements in set.
Set is immutable to .union() operation (or '|' operation).

Example

>>> s = set("Hacker")
>>> print s.union("Rank")
set(['a', 'R', 'c', 'r', 'e', 'H', 'k', 'n'])

>>> print s.union(set(['R', 'a', 'n', 'k']))
set(['a', 'R', 'c', 'r', 'e', 'H', 'k', 'n'])

>>> print s.union(['R', 'a', 'n', 'k'])
set(['a', 'R', 'c', 'r', 'e', 'H', 'k', 'n'])

>>> print s.union(enumerate(['R', 'a', 'n', 'k']))
set(['a', 'c', 'r', 'e', (1, 'a'), (2, 'n'), 'H', 'k', (3, 'k'), (0, 'R')])

>>> print s.union({"Rank":1})
set(['a', 'c', 'r', 'e', 'H', 'k', 'Rank'])

>>> s | set("Rank")
set(['a', 'R', 'c', 'r', 'e', 'H', 'k', 'n'])
Task
Students of District College have subscription of English and French newspapers. Some students have subscribed to only English, some have subscribed to only French and some have subscribed to both newspapers.

You are given two sets of roll numbers of students, who have subscribed to English and French newspapers. Your task is to find total number of students who have subscribed to at least one newspaper.

Input Format

First line contains, number of students who have subscribed to English newspaper. 
Second line contains, space separated list of roll numbers of students, who have subscribed to English newspaper.
Third line contains, number of students who have subscribed to French newspaper. 
Fourth line contains, space separated list of roll numbers of students, who have subscribed to French newspaper.

Constraints

0<Total number of students in college<1000
Output Format

Output total number of students who have at least one subscription.

Sample Input

9
1 2 3 4 5 6 7 8 9
9
10 1 2 3 11 21 55 6 8
Sample Output

13
Explanation

Roll numbers of students who have atleast one subscription:
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 21 and 55.
Hence, total is 13 students.

"""

e = input()
el = set(map(int,raw_input().split()))
f = input()
fl = set(map(int,raw_input().split()))

u = el.union(fl)

print u

print len(u)