How can I make ‘Spawn’ return the error that occurred when 'Started' is received?

[Capybara-1]

When I spawn an actor, if I need to initialize the actor upon receiving 'Started', and if initialization fails, the actor should not start successfully. How should I write this code? I noticed that after I receive 'Started', the spawn has already returned the Pid. However, I do not want this because I need the actor to stop when initialization fails and have the spawn return an error

[rogeralsing]

I would rather wrap all that in a helper function that handles all of this.
e.g. if your code fails to initialize, set some state of the actor to failed.
then add a message request+response where you can query that state.

func NewSomeActor() {
       	props := actor.PropsFromProducer(......)
        pid := system.Root.Spawn(props)
        res := system.Root.RequestFuture(pid, &SomeRequest {}).Result
        if res == .... {
                 //actor started successfully
        }
        else {
                  //actor failed to initialize
        }
}

Or if possible, you could do it even before proto.actor is involved at all.
You can set state in the actor upon producing it.

func() actor.Actor { return &helloActor{
     .....set state here
} }

you could create a function that resolves all deps and returns a Props if successful, or err if failed.
That way, you could catch this error before the actor is spawned.

[Capybara-1]

我宁愿将所有这些包装在一个处理所有这些的帮助程序函数中。例如，如果您的代码无法初始化，请将 actor 的某些状态设置为 failed。然后添加消息 request+response，您可以在其中查询该状态。

func NewSomeActor() {
       	props := actor.PropsFromProducer(......)
        pid := system.Root.Spawn(props)
        res := system.Root.RequestFuture(pid, &SomeRequest {}).Result
        if res == .... {
                 //actor started successfully
        }
        else {
                  //actor failed to initialize
        }
}

或者，如果可能的话，你甚至可以在 proto.actor 参与之前就这样做。您可以在生成 actor 时在 actor 中设置状态。

func() actor.Actor { return &helloActor{
     .....set state here
} }

您可以创建一个函数来解析所有 deps，如果成功，则返回 Props，如果失败，则返回 err。这样，您就可以在生成 actor 之前捕获此错误。

I have considered and tried the first method, but I am unable to determine how long the timeout for synchronous requests should be set. If the time is too long, it may affect the overall performance.

[Capybara-1]

新一期参

For the second approach, I might need to do some things using actor.Context during initialization, so it may not work as well.

[Capybara-1]

Currently, I am not sure if there will be any issues with the way I am doing it. The code is as follows:

func makeHook(factory BehaviorFactory, args ...any) actor.SpawnFunc {
	return func(actorSystem *actor.ActorSystem, id string, props *actor.Props, parentContext actor.SpawnerContext) (pid *actor.PID, err error) {
		hook := &hook{Behavior: factory(args...), Actor: makeActor(), factory: factory, args: args}
		wait := make(chan error)
		defer close(wait)
		fun := func(ctx actor.Context) {
			hook.update(ctx)
			hook.Errorf("--------------------------------> %s", ctx.Parent())
			hook.Do(func() {
				if err := hook.Init(hook); err != nil {
					hook.Debugf("behavior init failed: %s", err)
					hook.Exit()
					wait <- err
					return
				}
				hook.Debugf("behavior init ok.")
				wait <- nil
			})
			hook.Receive(ctx)
		}
		props = actor.PropsFromFunc(fun, actor.WithSupervisor(actor.DefaultSupervisorStrategy()))
		if pid, err = actor.DefaultSpawner(actorSystem, id, props, parentContext); err != nil {
			return nil, err
		}
		err = <-wait
		return
	}
}

func Spawn(alias Alias, factory BehaviorFactory, args ...any) (pid Pid, err error) {
	props := (&actor.Props{}).Configure(actor.WithSpawnFunc(makeHook(factory, args...)))
	if pid, err = root.ActorSystem.Root.SpawnNamed(props, string(alias)); err != nil {
		return
	}
	root.Children = append(root.Children, pid)
	return
}