Rotate an array of n elements to the right by k steps.
For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7]
is rotated to [5,6,7,1,2,3,4]
.
Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.
三步反转法
(XTYT)T = YX
这里需要特别注意,向右移动的步数 k 有可能大于数组的长度,因此要做个取模处理。
class Solution {
public void rotate(int[] nums, int k) {
int n = nums.length;
k %= n;
reverse(nums, 0, n - k - 1);
reverse(nums, n - k, n - 1);
reverse(nums, 0, n - 1);
}
private void reverse(int[] nums, int from, int to) {
while (from < to) {
int temp = nums[from];
nums[from++] = nums[to];
nums[to--] = temp;
}
}
}