Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
Example 1:
2
/ \
1 3
Binary tree [2,1,3]
, return true.
Example 2:
1
/ \
2 3
Binary tree [1,2,3]
, return false.
递归。带上两个参数,分别表示最小值和最大值。 左子树的最大值要小于根节点,右子树的最小值要大于根节点。
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public boolean isValidBST(TreeNode root) {
return isValidBST(root, Long.MIN_VALUE, Long.MAX_VALUE);
}
public boolean isValidBST(TreeNode root, long min, long max) {
if (root == null) {
return true;
}
return (min < root.val) && (root.val < max)
&& isValidBST(root.left, min, root.val)
&& isValidBST(root.right, root.val, max);
}
}