You are given an n x n 2D matrix representing an image.
Rotate the image by 90 degrees (clockwise).
Note: You have to rotate the image in-place, which means you have to modify the input 2D matrix directly. DO NOT allocate another 2D matrix and do the rotation.
Example 1:
Given input matrix =
[
[1,2,3],
[4,5,6],
[7,8,9]
],
rotate the input matrix in-place such that it becomes:
[
[7,4,1],
[8,5,2],
[9,6,3]
]
Example 2:
Given input matrix =
[
[ 5, 1, 9,11],
[ 2, 4, 8,10],
[13, 3, 6, 7],
[15,14,12,16]
],
rotate the input matrix in-place such that it becomes:
[
[15,13, 2, 5],
[14, 3, 4, 1],
[12, 6, 8, 9],
[16, 7,10,11]
]
题意是给一个 n x n 的二维数组,将数组元素顺时针旋转 90 度。需要直接修改当前数组。
思路是从外往内,一圈一圈的进行。其中每一圈的每个元素顺时针旋转 90 度,连续操作四次。注意边界,防止重复操作。
class Solution {
public void rotate(int[][] matrix) {
int n = matrix.length;
for (int i = 0; i < n / 2; i ++) {
for (int j = i; j < n - 1 - i; j ++) {
int temp = matrix[i][j];
matrix[i][j] = matrix[n - 1 -j][i];
matrix[n - 1 -j][i] = matrix[n - 1 -i][n - 1 -j];
matrix[n - 1 - i][n - 1 - j] = matrix[j][n - 1 -i];
matrix[j][n - 1 -i] = temp;
}
}
}
}