-
Notifications
You must be signed in to change notification settings - Fork 27
/
Copy path376.WiggleSubsequence.py
70 lines (61 loc) · 2.3 KB
/
376.WiggleSubsequence.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
'''
Given an integer array nums, return the length of the
longest wiggle sequence.
A wiggle sequence is a sequence where the differences
between successive numbers strictly alternate between
positive and negative. The first difference (if one
exists) may be either positive or negative. A sequence
with fewer than two elements is trivially a wiggle
sequence.
- For example, [1, 7, 4, 9, 2, 5] is a wiggle
sequence because the differences (6, -3, 5, -7, 3)
are alternately positive and negative.
- In contrast, [1, 4, 7, 2, 5] and [1, 7, 4, 5, 5]
are not wiggle sequences, the first because its
first two differences are positive and the second
because its last difference is zero.
A subsequence is obtained by deleting some elements
(eventually, also zero) from the original sequence,
leaving the remaining elements in their original order.
Example:
Input: nums = [1,7,4,9,2,5]
Output: 6
Explanation: The entire sequence is a wiggle sequence.
Example:
Input: nums = [1,17,5,10,13,15,10,5,16,8]
Output: 7
Explanation: There are several subsequences that achieve
this length. One is [1,17,10,13,10,16,8].
Example:
Input: nums = [1,2,3,4,5,6,7,8,9]
Output: 2
Constraints:
- 1 <= nums.length <= 1000
- 0 <= nums[i] <= 1000
Follow up: Could you solve this in O(n) time?
'''
#Difficulty: Medium
#26 / 26 test cases passed.
#Runtime: 32 ms
#Memory Usage: 14.3 MB
#Runtime: 32 ms, faster than 83.94% of Python3 online submissions for Wiggle Subsequence.
#Memory Usage: 14.3 MB, less than 73.64% of Python3 online submissions for Wiggle Subsequence.
class Solution:
def wiggleMaxLength(self, nums: List[int]) -> int:
i = 0
while i < len(nums)-1:
if nums[i] == nums[i+1]:
nums.pop(i)
else:
i += 1
if len(nums) > 1:
length = len(nums)
positive = nums[1] - nums[0] > 0
for i in range(length-1):
if (nums[i+1] - nums[i] > 0) == positive:
length -= 1
else:
positive = (nums[i+1] - nums[i] > 0)
return 1 + length
else:
return 1